Axis Of Symmetry Definition, Formula & Solved Examples - Byju's
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For a parabola, the axis of symmetry is given by the formula, \[\large x = \frac{-b}{2a} for \: Quadratic \: Equation,\: y = ax^{2}+bx+c\] Where, a and b are coefficients of x2 and x respectively. c is a constant term.
Example 1:
Find the axis of symmetry of the graph of y = \(\begin{array}{l}x^{2}\end{array} \)−6x+5, using the formula.
Solution:
Given,
y = x2 – 6x + 5
For a quadratic function in standard form, y = a\(\begin{array}{l}x^{2}\end{array} \)+bx+c, the axis of symmetry is a vertical line, x = \(\begin{array}{l}\frac{-b}{2a}\end{array} \) Here, a = 1, b = −6 and c = 5
Substituting the values of a and b,
x = -(-6)/2(1)
= 6/2
= 3 Therefore, the axis of symmetry is x = 3.
Example 2:
Find the axis of symmetry of the graph of y = 2x2 + 8x – 3, using the formula.
Solution:
Given,
y = 2x2 + 8x – 3
Comparing the given equation with the standard form y = ax2 + bx + c,
a = 2, b = 8, c = -3
And the axis of symmetry is a vertical line; x = -b/2a
Substituting the values of a and b,
x = -8/2(2)
= -8/4
= -2
Therefore, the axis of symmetry is x = -2.
Example 3:
If the axis of symmetry of the equation y = px2 – 12x – 5 is 2, then find the value of p.
Solution:
Given,
y = px2 – 12x – 5
Axis of symmetry is x = 2
For a quadratic function in standard form, y=a\(\begin{array}{l}x^{2}\end{array} \)+bx+c, the axis of symmetry is a vertical line, x = \(\begin{array}{l}\frac{-b}{2a}\end{array} \)
Here, a = p, b = -12, c = -5
According to the given,
-b/2a = 2
-(-12)/2p = 2
12 = 4p
12/4 = p
Therefore, p = 3
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