C - How To Create Delay Function According To Program Need?

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C - How to create delay function according to program need?

By: IncludeHelp, on 22 JAN 2017

Simple way to create delay function by running a loop certain time, let suppose while (1) is running 333333333 times in a second.

Based on this count we can create our own delay function, Here is the function

void delay(int seconds){ unsigned long int count=333333333,i,j; for(i=0;i<seconds;i++) for(j=0;j<count;j++); }

Consider the following program, which is printing text with current time after 1 and then 2 seconds delay:

#include <stdio.h> #include <time.h> //time related////////// time_t rawtime; struct tm * timeinfo; //////////////////////// void delay(int seconds){ unsigned long int count=333333333,i,j; for(i=0;i<seconds;i++) for(j=0;j<count;j++); } void printTime(void){ time ( &rawtime ); timeinfo = localtime ( &rawtime ); printf ( "Current local time and date: %s\n", asctime (timeinfo) ); } int main() { printf("Text1\n"); printTime(); delay(1); //delay for 1 second printf("Text2\n"); printTime(); delay(2); //delay for 2 seconds printTime(); printf("Text3\n"); return 0; }

Output

Text1 Current local time and date: Sun Jan 22 20:41:12 2017 Text2 Current local time and date: Sun Jan 22 20:41:13 2017 Current local time and date: Sun Jan 22 20:41:15 2017 Text3

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