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When do we divide throughout by a trigo function?
Posted on April 28, 2014
From Jimmy
How do you know when you can divide throughout by a trigo function in an equation, and when you are not supposed to?
If dividing by a trigo function causes you to lose a set of solution by that trigo function, then you must factorise.
e.g:
cos x + (sin x)(cos x) = 0
If we divide by cos x, we get
1 + sin x = 0
and our answer will only come from sine function.
However, if we choose to factorise, we get
(cos x)( 1 + sin x) = 0
cos x = 0 and 1 + sin x = 0
Thus, we will have another set of solutions from the cosine function. If this is the case, DO NOT divide by a trigo function.
Here’s another case:
2 (cos x) + 3 (sin x) = 0
If we divide by cos x, we get
2 + 3 (sin x / cos x) = 0
2 + 3 (tan x) = 0
tan x = -2/3
Here, it looks as though we lost 2 trigo functions, sine and cosine, and ended up with only a tangent function. Thinking that we might have lost 2 sets of answers. However, since the identity states that
tan x = (sin x)/(cos x)
Both sine and cosine have already been “considered” when you find the angles that satisfy the tangent function.
In summary, unless you get a tangent (or in some cases, a cotangent) when you divide by a cosine (or in some cases, sine), DO NOT EVER DIVIDE BY A TRIGO FUNCTION!
This entry was posted in Additional Mathematics, Trigonometry, Trigonometry and tagged additional mathematics, cancel out, cos, cosine, divide, equation, factorise, sin, sine, tan, tangent, trigonometry.
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