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When do we divide throughout by a trigo function?

Posted on April 28, 2014

From Jimmy

How do you know when you can divide throughout by a trigo function in an equation, and when you are not supposed to?

If dividing by a trigo function causes you to lose a set of solution by that trigo function, then you must factorise.

e.g:

cos x + (sin x)(cos x) = 0

If we divide by cos x, we get

1 + sin x = 0

and our answer will only come from sine function.

However, if we choose to factorise, we get

(cos x)( 1 + sin x) = 0

cos x = 0                and                1 + sin x = 0

Thus, we will have another set of solutions from the cosine function. If this is the case, DO NOT divide by a trigo function.

Here’s another case:

2 (cos x) + 3 (sin x) = 0

If we divide by cos x, we get

2 + 3 (sin x  /  cos x) = 0

2 + 3 (tan x) = 0

tan x = -2/3

Here, it looks as though we lost 2 trigo functions, sine and cosine, and ended up with only a tangent function. Thinking that we might have lost 2 sets of answers. However, since the identity states that

tan x = (sin x)/(cos x)

Both sine and cosine have already been “considered” when you find the angles that satisfy the tangent function.

In summary, unless you get a tangent (or in some cases, a cotangent) when you divide by a cosine (or in some cases, sine), DO NOT EVER DIVIDE BY A TRIGO FUNCTION!

This entry was posted in Additional Mathematics, Trigonometry, Trigonometry and tagged additional mathematics, cancel out, cos, cosine, divide, equation, factorise, sin, sine, tan, tangent, trigonometry.

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