Codingame : Power Of Thor - Episode 1 - Velog

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hoony.log로그인hoony.log로그인Codingame : Power of Thor - Episode 1Root(√)·2020년 8월 27일팔로우0python알고리즘

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https://www.codingame.com/training/easy/power-of-thor-episode-1

오늘 토르 라그나로크를 보고 나니 이 문제를 풀고 싶어져서 풀어봤다.

import sys import math # Auto-generated code below aims at helping you parse # the standard input according to the problem statement. # --- # Hint: You can use the debug stream to print initialTX and initialTY, if Thor seems not follow your orders. # light_x: the X position of the light of power # light_y: the Y position of the light of power # initial_tx: Thor's starting X position # initial_ty: Thor's starting Y position light_x, light_y, initial_tx, initial_ty = [int(i) for i in input().split()] # game loop while True: remaining_turns = int(input()) # The remaining amount of turns Thor can move. Do not remove this line. # Write an action using print # To debug: print("Debug messages...", file=sys.stderr, flush=True) # N if light_y < initial_ty and light_x == initial_tx : initial_ty -= 1 print("N") # NE elif light_x > initial_tx and light_y < initial_ty: initial_tx += 1 initial_ty -= 1 print("NE") # E elif light_x > initial_tx and light_y == initial_ty: initial_tx += 1 print("E") # SE elif light_x > initial_tx and light_y > initial_ty: initial_tx += 1 initial_ty += 1 print("SE") # S elif light_y > initial_ty and light_x == initial_tx : initial_ty += 1 print("S") # SW elif light_x < initial_tx and light_y > initial_ty: initial_tx -= 1 initial_ty += 1 print("SW") # W elif light_x < initial_tx and light_y == initial_ty: initial_tx -= 1 print("W") # NW else: initial_tx -= 1 initial_ty -= 1 print("NW") # A single line providing the move to be made: N NE E SE S SW W or NW profileRoot(√)Software Engineer팔로우이전 포스트

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