Continue Statement In C Programming Language - Codeforcoding
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- On August 31, 2024
- By Karmehavannan
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- Categories: Continue statements, Keyword in C language
- Tags: C language, flow of control
Continue statement in C programming language
C program continue statement
We will get to know the uses of Continue statement in C programming language in this tutorial (using for loop and while loop) – it controls the flow of control of loops in C language
Description
Continue is a keyword in the C language (some time called as a statement because ending with the semicolon)which is used to control the flow of loops.
Typically, this can be used inside of the while and for loop.
The continue statement provides the option to skip the current iteration(skip some steps) of the flow of control to the following loops until the flow of control exits the loops.
The syntax of the continue
continue;Flow diagram of continue

How continue works in C – control flow for loop
How to continue statement works in C – control flow – while loop
continue statement in for loop
Program 1
#include <stdio.h> #include <stdlib.h> int main() { int i; for(i=1; i<=10; i++) { if(i==5){ printf("Skipped this value :%d\n",i); continue; } printf("%d\n",i); } printf("End of loop\n"); getch(); return 0; }
When the above code is compiled and executed, it will produce the following results
1 2 3 4 skipped value :5 6 7 8 9 10 End of loop
When this program is executed, number 5 skipped by continue statement in for loop of C
Program 2
#include <stdio.h> #include <stdlib.h> int main() { int num; int sum=0; int i,n; printf("Enter any number \n"); scanf("%d",&n); for(i=1; i<=n; i++){ printf("Enter Number :%d\n",i); scanf("%d",&num); if(num==20){ continue; } sum=sum+num; } printf("Total value is :%d\n",sum); printf("End of program"); getch(); return 0; }
When the above code is compiled and executed, it will produce the following results
Enter any number 5 Enter number :1 10 Enter number :2 20 Enter number :3 30 Enter number :4 40 Enter number :5 50 Total value is :130 End of programNumber 20 skipped by continue statements from the addition
Continue in while loop in C
Program 3
#include <stdio.h> #include <stdlib.h> int main() { int i=1; while(i<=10){ if(i==6){ printf("Skipped value :%d\n",i); i++; continue; } printf("value %d\n",i); i++; } printf("End of loop\n"); getch(); return 0; }
When the above code is compiled and executed, it will produce the following results
value 1 value 2 value 3 value 4 value 5 Skipped value :6 value 7 value 8 value 9 value 10 End of loop
When this program is executed, number 6 skipped the continue statement in for loop
Program 4
#include <stdio.h> #include <stdlib.h> int main() { int num; int sum=0; int i,n; printf("Enter any number \n"); scanf("%d",&n); i=1; while(i<=n){ printf("Enter Number :%d\n",i); scanf("%d",&num); if(num==25){ continue; ++i; } sum=sum+num; ++i; } printf("Total value is :%d\n",sum); printf("End of program\n"); getch(); return 0; }
When the above code is compiled and executed, it will produce the following results
Enter any number 5 Enter number :1 10 Enter number :2 15 Enter number :3 20 Enter number :4 25 Enter number :5 30 Total value is :110 End of programWhen this program is executed, number 25 is skipped from calculating total by continue statement in for loop
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