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Crnpfr JtME What Happened When Two Fruit Companies Merged ? Fr&ac aZ below, Ird D8 equadon &l tho Bne Der7ng UoUZWte wia 100 EREn point Cida Da Iwa kbers naxl l0 tha COTc equtor- in tha Fec Dons 4 tne Lakoin 0i ta p7ge taat crain 52 Funbe Tic FE FELEn= 0eft: O EINeE" 47 (1, 5) (2, 7 [w54{79 Cs ) y=3*+2 1) (3. ~kS 2+8 52423+6 60 % -21 79*2p5 y=z*-4 J= -ax+5 JE2-9 L3 + Y=4+7 12 5) (4 21 Y=2t' (-3 75) (-",3) Answers; (3, -1} (-6, -4) y=-4+4 74, 1) (-47) y=3t+} Y=-*+2 Y=-2-1 (-1,2)12, 4 y=-1*+2 -41(2 Q) Y=j*-2 v=3+ Y=a-2 ye#x-{ 31) (-3,5) 10l10 Crnpfr JtME What Happened When Two Fruit Companies Merged ? Fr&ac aZ below, Ird D8 equadon &l tho Bne Der7ng UoUZWte wia 100 EREn point Cida Da Iwa kbers naxl l0 tha COTc equtor- in tha Fec Dons 4 tne Lakoin 0i ta p7ge taat crain 52 Funbe Tic FE FELEn= 0eft: O EINeE" 47 (1, 5) (2, 7 [w54{79 Cs ) y=3*+2 1) (3. ~kS 2+8 52423+6 60 % -21 79*2p5 y=z*-4 J= -ax+5 JE2-9 L3 + Y=4+7 12 5) (4 21 Y=2t' (-3 75) (-",3) Answers; (3, -1} (-6, -4) y=-4+4 74, 1) (-47) y=3t+} Y=-*+2 Y=-2-1 (-1,2)12, 4 y=-1*+2 -41(2 Q) Y=j*-2 v=3+ Y=a-2 ye#x-{ 31) (-3,5) 10l10 Show more…

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Calculus: Early Transcendentals James Stewart 8th Edition

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Submit Thanks for your feedback! Crnpfr JtME What Happened When Two Fruit Companies Merged ? Fr&ac aZ below, Ird D8 equadon &l tho Bne Der7ng UoUZWte wia 100 EREn point Cida Da Iwa kbers naxl l0 tha COTc equtor- in tha Fec Dons 4 tne Lakoin 0i ta p7ge taat crain 52 Funbe Tic FE FELEn= 0eft: O EINeE" 47 (1, 5) (2, 7 [w54{79 Cs ) y=3*+2 1) (3. ~kS 2+8 52423+6 60 % -21 79*2p5 y=z*-4 J= -ax+5 JE2-9 L3 + Y=4+7 12 5) (4 21 Y=2t' (-3 75) (-",3) Answers; (3, -1} (-6, -4) y=-4+4 74, 1) (-47) y=3t+} Y=-*+2 Y=-2-1 (-1,2)12, 4 y=-1*+2 -41(2 Q) Y=j*-2 v=3+ Y=a-2 ye#x-{ 31) (-3,5) 10l10 Play audio Feedback Powered by NumerAI

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Suppose that the total profit in hundreds of dollars from selling x items is given by P(x) = 2x^2 - 7x + 6. Complete parts a through d below. a. Find the average rate of change of profit as x changes from 2 to 4. $ per item b. Find the average rate of change of profit as x changes from 2 to 3. $ per item c. Find and interpret the instantaneous rate of change of profit with respect to the number of items produced when x = 2. (This number is called the marginal profit at x = 2.) $ per item What does this result mean? Choose the correct answer below. A. When 2 items are sold, the profit is increasing at the rate of $ per item. B. When items are sold for $, the profit is decreasing at the rate of $2 per item. C. When 2 items are sold, the profit is decreasing at the rate of $ per item. D. When items are sold for $, the profit is increasing at the rate of $2 per item. d. Find the marginal profit at x = 4. $ per item

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40 years ago, the interest rate was 20%. Over the past decade, it has increased by 50%. Now, what can you conclude? The interest rate decade ago was 20% because 50 + 10 = 60, and 100 - 60 = 40. The interest rate decade ago was 20% because 50 * 0.2 = 10, 10 * 50 = 500, and 30 + 150 = 180. You can't conclude anything because the statement is incomplete. The interest rate decade ago was 20% because 60 * 0.2 / 10, and 10 = 30. You can't conclude anything because not enough information is given in the statement. The interest rate decade ago was 20% because 50 - 30 = 20.

Adi S.

Let y = f(x, y) = z = sin(xy^6) At (x, y) = (3π/2, -1), z = sin(3π/2 (-1)^6) = sin(3π/2 (1)) z = -1 Let (x0, y0, z0) = (3π/2, -1, -1) The Equation of the tangent line to the function z = f(x, y) at (x0, y0, z0) is z - z0 = fx(x0, y0)(x - x0) + fy(x0, y0)(y - y0) fx = d/dx sin(xy^6) = cos(xy^6) d/dx xy^6 = cos(xy^6) y^6 d/dx x fx = cos(xy^6) y^6(1) = y^6 cos(xy^6) fy = cos(xy^6) x d/dy y^6 = cos(xy^6) x (6y^6-1) fy = 6xy^5 cos(xy^6) fx(x0, y0) = (-1)^6 cos(3π/2) = 0 fy(x0, y0) = 6(3π/2) (-1)^5 cos(3π/2) = 0 z - (-1) = 0 + 0 z = -1 or z + 1 = 0 S(t) = t^3 - 9t^2 + 24t - 11 s'(t) = Velocity = V(t) = d/dt t^3 - 9 d/dt t^2 + 24 d/dt t - d/dt 11 s'(t) = 3t^3-1 - 9(2t) + 24(1) - 0 V(t) = s'(t) = 3t^2 - 18t + 24 v(t) = 0 ⇒ 3(t^2 - 6t + 8) = 0 t^2 - 6t + 8 = 0 t^2 - 4t - 2t + 8 = 0 t(t - 4) - 2(t - 4) = 0 (t - 2)(t - 4) = 0 t = 2, 4 Distance traveled in the intervals [1, 2], [2, 4], [4, 6] | f(2) - f(1) | = | 9 - 5 | = | 4 | = 4 | f(4) - f(2) | = | 5 - 9 | = | -4 | = 4 | f(6) - f(4) | = | 25 - 5 | = | 20 | = 20 Total distance = 4 + 4 + 20 = 28

Madhur L.

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