Definition, Graph, How To Find Critical Points? - Cuemath

Critical Point

The concept of critical point is very important in Calculus as it is used widely in solving optimization problems. The graph of a function has either a horizontal tangent or a vertical tangent at the critical point. Based upon this we will derive a few more facts about critical points.

Let us learn more about critical points along with its definition and how to find it from a function and from a graph along with a few examples.

1.	What is a Critical Point of a Function?
2.	Finding Critical Points
3.	Critical Points on a Graph
4.	Critical Points of Multivariable Functions
5.	FAQs on Critical Points

What is a Critical Point of a Function?

A critical point of a function y = f(x) is a point (c, f(c)) on the graph of f(x) at which either the derivative is 0 (or) the derivative is not defined. But how is a critical point related to the derivative? We know that the slope of a tangent line of y = f(x) at a point is nothing but the derivative f'(x) at that point. We already have seen that a function has either a horizontal or a vertical tangent at the critical point.

• Horizontal tangent at (c, f(c)) ⇒ Slope = 0 ⇒ f '(c) = 0
• Vertical tangent at (c, f(c)) ⇒ Slope = undefined ⇒ f'(c) is NOT defined

Critical Point of a Function Definition

Based upon the above discussion, a critical point of a function is mathematically defined as follows. A point (c, f(c)) is a critical point of a continuous function y = f(x) if and only if

• c is in the domain of f(x).
• Either f '(c) = 0 or f'(c) is NOT defined.

Critical Values of a Function

The critical values of a function are the values of the function at the critical points. For example, if (c, f(c)) is a critical point of y = f(x) then f(c) is called the critical value of the function corresponding to the critical point (c, f(c)).

Finding Critical Points

Here are the steps to find the critical point(s) of a function based upon the definition. To find the critical point(s) of a function y = f(x):

• Step - 1: Find the derivative f '(x).
• Step - 2: Set f '(x) = 0 and solve it to find all the values of x (if any) satisfying it.
• Step - 3: Find all the values of x (if any) where f '(x) is NOT defined.
• Step - 4: All the values of x (only which are in the domain of f(x)) from Step - 2 and Step - 3 are the x-coordinates of the critical points. To find the corresponding y-coordinates, just substitute each of them into the function y = f(x). Writing all such pairs (x, y) would give us all critical points.

Example to Find Critical Points

Let us find the critical points of the function f(x) = x1/3 - x. For this, we first have to find the derivative.

Step - 1: f '(x) = (1/3) x-2/3 - 1 = 1 / (3x2/3)) - 1

Step - 2: f'(x) = 0 1 / (3x2/3)) - 1 = 0 1 / (3x2/3)) = 1 1 = 3x2/3 1/3 = x2/3 Cubing on both sides, 1/27 = x2 Taking square root on both sides, ± 1/(3√3) = x (or) x = ± √3 / 9 So x = √3 / 9 and x = - √3 / 9

Step - 3: f'(x) is NOT defined at x = 0.

Step - 4: The domain of f(x) is the set of all real numbers and hence all x-values from Step - 2 and Step - 3 are present in the domain of f(x) and hence all these are the x-coordinates of the critical points. Let us find their corresponding y-coordinates:

• When x = √3 / 9, y = (√3 / 9)1/3 - (√3 / 9) = 2√3 / 9
• When x = -√3 / 9, y = (-√3 / 9)1/3 - (-√3 / 9) = -2√3 / 9
• When x = 0, y = 01/3 - 0 = 0

Therefore, the critical points of f(x) are (√3 / 9, 2√3 / 9), (-√3 / 9, -2√3 / 9) and (0, 0). In this example, the y-coordinates of critical points which are 2√3 / 9, -2√3 / 9, and 0 are the critical values of the function.

Critical Points on a Graph

We have already seen how to find the critical points when a function is given. Now, we will see how to find the critical points from the graph of a function. The following points would help us in identifying the critical points from a given graph.

• We know that the points at which the tangents are horizontal are critical points. So at all such critical points, the graph either changes from "increasing to decreasing" or from "decreasing to increasing". It means the curve may have (but not necessarily) a local maximum or a local minimum at critical points. Here is an example. In the above figure, (0, 0) and (2, 4) are critical points as we have local minimum and local maximum respectively at these points. Note that we can draw horizontal tangents also at these points.
• The points on the curve where we can draw a vertical tangent are also critical points. In the above figure, (0, 0) is a critical point.
• The sharp turning points (cusps) are also critical points. In the above figure, (0, 0) is a critical point.

Critical Points of Multivariable Functions

For finding the critical points of a single-variable function y = f(x), we have seen that we set its derivative to zero and solve. But to find the critical points of multivariable functions (functions with more than one variable), we will just set every first partial derivative with respect to each variable to zero and solve the resulting simultaneous equations. For example:

• To find the critical points of a two-variable function f(x, y), set ∂f / ∂x = 0 and ∂f / ∂y = 0 and solve the system of equations.
• To find the critical points of a three-variable function f(x, y, z), set ∂f / ∂x = 0, ∂f / ∂y = 0, and ∂f / ∂z = 0 and solve the resultant system of equations.

Example of Finding Critical Points of a Two-Variable Function

Let us find the critical points of f(x, y) = x2 + y2 + 2x + 2y. For this, we have to find the partial derivatives first and then set each of them to zero.

∂f / ∂x = 2x + 2 and ∂f / ∂y = 2y + 2

If we set them to zero,

• 2x + 2 = 0 ⇒ x = -1
• 2y + 2 = 0 ⇒ y = -1

So the critical point is (-1, -1).

Important Points on Critical Points:

• The points at which horizontal tangent can be drawn are critical points.
• The points at which vertical tangent can be drawn are critical points.
• All sharp turning points are critical points.
• Local minimum and local maximum points are critical points but a function doesn't need to have a local minimum or local maximum at a critical point. For example, f(x) = 3x4 - 4x3 has critical point at (0, 0) but it is neither a minimum nor a maximum.
• The critical point of a linear function does not exist.
• The critical point of a quadratic function is always its vertex.

Related Topics:

• Derivative Calculator
• Applications of Derivatives
• Maxima and Minima
• First Derivative Test
• Second Derivative Test