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  • Thread starter kickingtoad
  • Start date Dec 3, 2010
K

kickingtoad

New member
Joined Nov 12, 2010 Messages 20 Homework 2-1, problem 2 lauren-Q-lunstrum-Q-95-4209-setHomework2-1prob2image1.png The function h(x) given in the above graph. Enter the corresponding function value in each answer space below: h(0)= h(5)= h(3)= h(4)= I know this is a parabola but I'm confused about how to formulate the function as in units to the right and units up. \(\displaystyle {x{2}...}\) D

DrSteve

Banned
Joined Nov 14, 2010 Messages 87 In the expression h(x) = y , x is the x-value of the point on the graph, and y is the y-value of the point on the graph. So, for example, since (3,2) is on the graph we have h(3) = 2 mmm4444bot

mmm4444bot

Super Moderator
Joined Oct 6, 2005 Messages 10,825 h(0) is the y-intercept. However, the y-intercept is not shown, on this particular graph. Perhaps, you're supposed to interpret the graph as a sloppy, quick-and-dirty graph, followed by GUESSING that h(0) is supposed to be 10. I dunno. For the rest of it, do you understand the given function notation? You stated difficulty "to formulate the function". I'm not sure what that means. They are not asking for a formulation, in this exercise. Also, what does your typing "x2..." denote? K

kickingtoad

New member
Joined Nov 12, 2010 Messages 20 Okay, I see what you're saying about finding the y value on the graph based on the x value. I was trying to find the solutions by formulating the function from looking at the graph. like \(\displaystyle {(x^{2}-3)+2}\) Since -3 means three to the right, and +2 means move up two. I'm just confused on whether the -3 or +2 goes in the brackets. I was able to get 3 correct y values with the function, except 1 came out wrong... D

DrSteve

Banned
Joined Nov 14, 2010 Messages 87 I think that you're saying that you want to write an equation for the parabola in standard form. This equation is \(\displaystyle y = a(x-3)^2+2\) for some constant a. We can find a by substituting in a point that we know is on the graph, like (4,3) \(\displaystyle 3 = a(4-3)^2+2\) \(\displaystyle 3 = a+2\) \(\displaystyle 1 = a\) So the equation is \(\displaystyle y =(x-3)^2+2\) You must log in or register to reply here. Share: Facebook X (Twitter) Reddit Pinterest Tumblr WhatsApp Email Share Link
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Tag » How To Find Function Value