Finding Parametric Equations For A Graph

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Home > Math > Pre Calculus > Finding Parametric Equations for a Graph Finding Parametric Equations for a Graph A set of parametric equations is not unique for a given graph. For example the following sets of parametric equations result in the same rectangular equation and thus represent the same graph.

First Parametric equation

Second Parametric Equation

Rectangular Equation

x=4 t 2 −4

y = t

x=4 y 2 −4

x= t 2 −4

y= t 2

2y = t

x = (2y)2 - 4

x=4 y 2 −4

However, given a rectangular equation and an equation describing the parameter in terms of one of the two variables, a set of parametric equations can be determined. To find a set of parametric equations for the graph represented by y = x2 + 2 given t = x + 2, let t = x. Switching the roles of t and x in this equation gives one of the parametric equations:

t=x+2→x=t+2

Now substitute the expression for x into the rectangular equation, y = x2 + 2 to obtain the second parametric equation.

y= x 2 +2

y= ( t+2 ) 2 +2

y= t 2 +4t+4+2

y= t 2 +4t+6

Thus the set of parametric equations for the graph represented by y = x2 + 2 is,

x=t+2

y= t 2 +4t+6

Now that both parametric equations have been determined, the overall graph can be drawn with selected values for the parameter.

t

-2

-1

0

1

2

x = t + 2

0

1

2

3

4

y = t2 + 4t + 6

2

3

6

11

18

GUIDELINES FOR FINDING THE PARAMETRIC EQUATIONS FOR A GRAPH:

1. Take the parameter equation and switch the roles of the parameter and the other variable. This will result in one parametric equation.2. Substitute the expression for the variable in Step 1 into the rectangular equation. This will result in the second parametric equation.3. Sketch the curve.

Let's try a couple of examples. Example 1: Find a set of parametric equations for the rectangular equation y = x2 + 1, given t = 2 - x. Then sketch a graph locating points at 0≤t≤3 and indicate the orientation of the curve.

Step 1: Take the parameter equation and switch the roles of the parameter and the other variable.

Let t = x and rewrite the parameter equation by switching t and x.

t = 2 - x Original

x = 2 - t Switch t and x

Step 2: Substitute the expression for the variable in Step 1 into the rectangular equation

y= x 2 +1 Original

y= ( 2−t ) 2 +1 Substitute

y=( 4−4t+ t 2 )+1 Square

y=5−4t+ t 2 Add

Step 3: Sketch the curve.

List the two parametric equations and sketch a graph locating points at 0≤t≤3 and indicate the orientation of the curve.

Rectangular Equation: y= x 2 +1

Parametric Equations: x = 2 - t, y=5−4t+ t 2

t

0

1

2

3

x

x = 2 - t

2

1

0

-1

y

y = 5 - 4t + t2

5

2

1

2

Example 2: Find a set of parametric equations for the rectangular equation y= 2 x 2 +1 , given t= x . Then sketch a graph locating points at t = {0,1,2,3,4} and indicate the orientation of the curve.

Step 1: Take the parameter equation and switch the roles of the parameter and the other variable.

t= x Original

x= t Switch t and x

Step 2: Substitute the expression for the variable in Step 1 into the rectangular equation

y= 2 x 2 +1 Original

y= 2 t 2 +1 Substitute

y= 2 t+1 Square

Step 3: Sketch the curve.

List the two parametric equations and sketch a graph locating points at t = {0, 1, 2, 3, 4} and indicate the orientation of the curve.

Rectangular Equation: y= 2 x 2 +1

Parametric Equations: x= t , y= 2 t+1

t

0

1

2

3

4

x

x= t

0

1

2

3

2

y

y= 2 t+1

2

1

2 3

1 2

2 5

Note that the domain of the graph is x≥0 because the domain of the parametric equation, t= x , limits x to values of zero or greater.

Related Links: Math algebra Parametric Equations: Derivatives Inverse Functions: Graphs Pre Calculus

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