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• For 4d35s2 configuration belon...

AnswerQuestion Answers for Class 12Class 12 BiologyClass 12 ChemistryClass 12 EnglishClass 12 MathsClass 12 PhysicsClass 12 Social ScienceClass 12 Business StudiesClass 12 EconomicsQuestion Answers for Class 11Class 11 EconomicsClass 11 Computer ScienceClass 11 BiologyClass 11 ChemistryClass 11 EnglishClass 11 MathsClass 11 PhysicsClass 11 Social ScienceClass 11 AccountancyClass 11 Business StudiesQuestion Answers for Class 10Class 10 ScienceClass 10 EnglishClass 10 MathsClass 10 Social ScienceClass 10 General KnowledgeQuestion Answers for Class 9Class 9 General KnowledgeClass 9 ScienceClass 9 EnglishClass 9 MathsClass 9 Social ScienceQuestion Answers for Class 8Class 8 ScienceClass 8 EnglishClass 8 MathsClass 8 Social ScienceQuestion Answers for Class 7Class 7 ScienceClass 7 EnglishClass 7 MathsClass 7 Social ScienceQuestion Answers for Class 6Class 6 ScienceClass 6 EnglishClass 6 MathsClass 6 Social ScienceQuestion Answers for Class 5Class 5 ScienceClass 5 EnglishClass 5 MathsClass 5 Social ScienceQuestion Answers for Class 4Class 4 ScienceClass 4 EnglishClass 4 MathsFor $4{d^3}5{s^2}$ configuration belongs to which group?A. IIAB. IIBC. VBD. IIIBAnswerVerified577.5k+ viewsHint: The configuration $4{d^3}5{s^2}$is the outer electronic configuration of element Niobium which is represented by Nb. Its atomic number is 41. n is the number of electrons present in s orbital.Complete answer:The electronic configuration of the element niobium (Nb) is $[Kr]4{d^3}5{s^2}$.The symbol [Kr] is the condensed electron configuration of the element krypton present in the ground state. It represents all the electrons present in this element. The ground state atom of this element will contain the electronic configuration $4{d^3}5{s^2}$. This element will be present just beneath the period in which krypton is present. Krypton is the last element of the fourth period. Therefore, the element is present in the fifth period of the periodic table. The value of n is 5.The block of the element present in the periodic table is determined by the type of the occupied electron orbital with highest potential energy. The electron with the highest potential energy in the ground state atom of the element is present is 4d orbital. Therefore, the element is present in the d-block of the periodic table.The group of the element is calculated by the formula as shown below.$Group = ns + (n - 1)d{e^ - }$$\Rightarrow Group = 2 + 3$$\Rightarrow Group = 5$Therefore, the group in which $4{d^3}5{s^2}$ configuration belongs is VB.Therefore, the correct option is C.Note:The electron consisting of the highest potential energy in the ground state atom of the element is obtained using the Aufbau diagram. The actual electronic configuration of niobium is $[Kr]4{d^4}5{s^1}$ but the new electronic configuration is $[Kr]4{d^3}5{s^2}$which is stabilized with the Aufbau principle.Recently Updated PagesThe total number of structural isomers possible for class 12 chemistry CBSEWhat is a parallel plate capacitor Deduce the expression class 12 physics CBSEMaster Class 12 Social Science: Engaging Questions & Answers for SuccessMaster Class 12 Physics: Engaging Questions & Answers for SuccessMaster Class 12 Maths: Engaging Questions & Answers for SuccessMaster Class 12 Economics: Engaging Questions & Answers for SuccessThe total number of structural isomers possible for class 12 chemistry CBSEWhat is a parallel plate capacitor Deduce the expression class 12 physics CBSEMaster Class 12 Social Science: Engaging Questions & Answers for SuccessMaster Class 12 Physics: Engaging Questions & Answers for SuccessMaster Class 12 Maths: Engaging Questions & Answers for SuccessMaster Class 12 Economics: Engaging Questions & Answers for Success

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