Lesson 6: Rationalization - Precalculus Review Workshop
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Lesson 6: Rationalization
When we rationalize a denominator, we are trying to find an equivalent expression without a square root in the denominator. To rationalize the denominator, first identify the form from the chart below, then multiply by the given rational expression. $A$, $B$ and $C$ represent any non-zero expressions.| Form | Multiply by |
|---|---|
| $\displaystyle \frac{A}{\sqrt{B}}$ | $\displaystyle \frac{\sqrt{B}}{\sqrt{B}}$ |
| $\displaystyle \frac{A}{\sqrt{B} \pm \sqrt{C}}$ | $\displaystyle \frac{\sqrt{B} \textrm{ }\mp \textrm{ }\sqrt{C}}{\sqrt{B} \textrm{ }\mp \textrm{ }\sqrt{C}}$ |
| $\displaystyle \frac{A}{\sqrt{B} \pm C}$ | $\displaystyle \frac{\sqrt{B}\textrm{ }\mp \textrm{ }C}{\sqrt{B}\textrm{ }\mp \textrm{ }C}$ |
| Form | Multiply by |
|---|---|
| $\displaystyle \frac{\sqrt{A}}{B}$ | $\displaystyle \frac{\sqrt{A}}{\sqrt{A}}$ |
| $\displaystyle \frac{\sqrt{B}\pm\sqrt{C}}{A}$ | $\displaystyle \frac{\sqrt{B} \textrm{ }\mp \textrm{ }\sqrt{C}}{\sqrt{B} \textrm{ }\mp \textrm{ }\sqrt{C}}$ |
| $\displaystyle \frac{\sqrt{B}\pm C}{A}$ | $\displaystyle \frac{\sqrt{B}\textrm{ }\mp \textrm{ }C}{\sqrt{B}\textrm{ }\mp \textrm{ }C}$ |
Problem Set 1.6
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