PARTS PER MILLION CONVERSIONS - Analytical Chemistry

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Dilution Formula : C1V1 = C2V2

This equation applies to all dilution problems.

C1 (initial conc) x V1 (initial volume) = C2 (final conc) x V2 (final volume)

Example : What volume of 6.00 ppm solution must be used to give 4.00 liters of a 0.100 ppm solution?

C1 = 6.00 ppm V1 = unknown C2 = 0.100 ppm V2 = 4 liters = 4000 mls

V1 = (C2 x V2) / C1

= (0.100 X 4000) / 6.00 = 400 / 6.00 = 66.7 mls.

This means that 66.7 mls of the 6.00ppm solution diluted to a final volume of 4 liters will give a concentration of 0.100 ppm.

The Formula below can be used to calculate the the V1 component only.

req is the value you want.

req ppm x req vol -------------------------- = no of mls for req vol stock Example : Make up 50 mls vol of 25 ppm from 100 ppm standard. 25 x 50 / 100 = 12.5 mls. i.e. 12.5 mls of 100 ppm in 50 ml volume will give a 25 ppm solution

Serial dilutions

Making up 10-1 M to 10-5 M solutions from a 1M stock solution. Pipette 10 ml of the 1M stock into a 100 ml volumetric flask and make up to the mark to give a 10-1 M soln. Now, pipette 10 ml of this 10-1 M soln. into another 100 ml flask and make up to the mark to give a 10-2 M soln. Pipette again, 10 ml of this 10-2 M soln. into yet another 100 ml flask and make up to mark to give a 10-3 M soln. Pipette a 10 ml of this 10-3 M soln. into another 100 ml flask and make up to mark to give a 10-4 M soln. And from this 10-4 M soln. pipette 10 ml into a 100 ml flask and make up to mark to give a final 10-5 M solution. ppm concentration conversions Signature: Dhanlal De Lloyd, Chem. Dept, The University of The West Indies, St. Augustine campusThe Republic of Trinidad and Tobago. Copyright: delloyd2000© All rights reserved.

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