Reduced Row Echelon Form - StatLect
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by Marco Taboga, PhD
A matrix is said to be in reduced row echelon form when it is in row echelon form and its basic columns are vectors of the standard basis (i.e., vectors having one entry equal to 1 and all the other entries equal to 0).
When the coefficient matrix of a linear system is in reduced row echelon form, it is straightforward to derive the solutions of the system from the coefficient matrix and the vector of constants.
Table of contents
Prerequisites
Definition of reduced row echelon form
How to solve a system in reduced echelon form
How to transform a system to reduced row echelon form
Solved exercises
Exercise 1
Exercise 2
Prerequisites
In order to understand this lecture, you should first read the lecture on the Row echelon form.
In particular, remember that a matrix is in row echelon form if and only if:
-
all its non-zero rows have an entry, called pivot, that is non-zero and has only zero entries below it and to its left;
-
zero-rows (if there are any) are below the non-zero rows.
When a column of a matrix in row echelon form contains a pivot, it is called a basic column. When it does not contain a pivot, we say that it is a non-basic column.
Example DefineThe matrix
is in row echelon form. Its pivots are the underlined entries
,
,
. All the columns of
are basic. There is not any non-basic column.
Example The matrixis in row echelon form. Its pivots are
and
. The first and third column are basic, the second is non-basic.
Definition of reduced row echelon form
A precise definition of reduced row echelon form follows.
Definition We say that a matrix is in reduced row echelon form if and only if it is in row echelon form, all its pivots are equal to 1 and the pivots are the only non-zero entries of the basic columns.
We show some matrices in reduced row echelon form in the following examples.
Example The matrixis in reduced row echelon form. It has one zero row (the third), which is below the non-zero rows. The first and the second row are non-zero, but have a pivot (
and
, respectively). The two pivots are equal to
and they are the only non-zero entries in their respective columns.
Example The matrixis in row echelon form because both of its rows have a pivot. However, it is not in reduced row echelon form because there is a non-zero entry in the column of the pivot
.
Example The matrixis in reduced row echelon form. Its zero rows are below the non-zero rows. The first and the second row are non-zero, but have a pivot (
and
, respectively). The pivots are equal to
and they are the only non-zero entries in their respective columns.
Example The identity matrixis in reduced row echelon form.
How to solve a system in reduced echelon form
Consider a linear system where
is a
matrix of coefficients,
is an
vector of unknowns, and
is a
vector of constants.
The system is said to be in reduced row echelon form if the matrix is in reduced row echelon form.
As explained in the lecture on Matrix multiplication and linear combinations, the product can be written as a linear combination of the columns of
:
where the coefficients of the combination are the unknowns .
If an unknown multiplies a basic column, it is called a basic variable. Otherwise, if it corresponds to a non-basic column, it is called a non-basic variable.
Example Define a system whose matrix of coefficientsis in reduced row echelon form, and
Then,
is non-basic and
and
are basic.
Since the reduced echelon form is a special case of the echelon form, the conditions for the existence of a solution of a system in the latter form apply, and we can use the back-substitution algorithm to solve the system.
Remember how the back-substitution algorithm works:
-
if there are
basic columns, we choose
values arbitrarily for the non-basic variables (i.e., for the unknowns corresponding to the non-basic columns);
-
for
, if the
-th row is non-zero and
is the basic variable corresponding to the pivot of the
-th row, we set
If is in reduced row echelon form, then
, so that equation 1 becomes
Furthermore, the coefficients in equation 2 are equal to
when
is the index of a basic column.
Example Consider a system in reduced row echelon form with augmented matrix
Since the third column is non basic, is a non-basic variable and we can choose it arbitrarily. We choose
We skip the third row because it is zero. On the second row, we have
and on the first one we have
How to transform a system to reduced row echelon form
The standard algorithm used to transform a system into an equivalent system in reduced row echelon form is called Gauss Jordan elimination.
Solved exercises
Below you can find some exercises with explained solutions.
Exercise 1
Determine whether the matrixis in reduced row echelon form.
Let us first underline the pivots:
Each non-zero row has a pivot. Furthermore, there is a zero row, but it is below the non-zero rows. Therefore is in echelon form. It is not in reduced form because the third column is basic but it contains a non-zero element that is not a pivot.
Exercise 2
Determine whether the matrix
is in reduced row echelon form.
Let us first underline the pivots:
Each non-zero row has a pivot. Moreover, the only zero row (the fourth) is preceded by the non-zero rows. Therefore is in echelon form. It is also in reduced form because all the pivots are equal to
and the non-pivotal elements in the basic columns are all equal to
.
How to cite
Please cite as:
Taboga, Marco (2021). "Reduced row echelon form", Lectures on matrix algebra. https://www.statlect.com/matrix-algebra/reduced-row-echelon-form.
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