The word solubility is all about calculating the amount of solute dissolved in a given solvent. The simple concept of solubility of a substance is the molarity of the material under excessive undissolved material in a solution at chemical equilibrium. Since the solubility is temperature-dependent there should be uniform temperature throughout the system. The solubility formula is expressed as \(\begin{array}{l}S = \sqrt{K_{sp}}\end{array} \)
The expression for solubility product has the same general form than other equilibrium constant expressions and KSP is called solubility product constant ”
Example 1
The molar solubility of tin iodide SnI2 is 1.28 x 10-2 mol/L. Calculate the Ksp of this compound.
Solution:
The solubility equilibrium of SnI2 is
SnI2(s) ⇋⇋ Sn2+(aq) + 2I–(aq)
The Ksp expression is written as
Ksp = [Sn2+][I–]2
1 mol of SnI2 Produces 1.0 mol of Sn2+, but 2.0mol of I–.
[Sn2+] = 1.28 × 10-2M
[I–] = (2) × 1.28 × 10-2M
[I–] = 2.56 × 10-2M
Substitute these values in Ksp expression
Ksp = (1.28 ×× 10-2M)(2.56 × 10-2M)2
Therefore, Ksp = 8.4 × 10-6 M2
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Waleed khalid August 4, 2019 at 9:34 am
Its really good and very helpful thank you for clearing my doubts
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Gold Ekanem April 22, 2020 at 11:54 pm
Thanks so much for helping me to understand more better
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