Solving Radical Equations - Varsity Tutors
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Beginner
Solving Radical Equations
Study GuideKey Definition
A radical equation is an equation in which the variable is under a radical, such as $\sqrt{x}$.Important Notes
- Isolate the radical expression before squaring both sides.
- Check for extraneous solutions after solving.
- Square both sides carefully to eliminate the square root.
- Ensure the equation is simplified before solving.
- Verify your solution by substituting it back into the original equation.
Mathematical Notation
$\sqrt{x}$ represents the square root of $x$$+$ represents addition$-$ represents subtraction$\times$ or $*$ represents multiplication$\div$ or $/$ represents divisionRemember to use proper notation when solving problemsWhy It Works
Squaring both sides of an equation allows us to eliminate the square root, making it possible to solve for the variable directly.Remember
Always check for extraneous solutions by substituting back into the original equation.Quick Reference
Square Root Property:$\sqrt{x^2} = |x|$Understanding Solving Radical Equations
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BeginnerStart here! Easy to understand
BeginnerIntermediateAdvancedBeginner Explanation
A radical equation is one where the variable is inside a square root, like $\sqrt{x} = 3$.Now showing Beginner level explanation.Practice Problems
Test your understanding with practice problems
1Quick Quiz
Single Choice QuizBeginnerSolve the equation $\sqrt{x} = 4$. What is $x$?
A$16$B$4$C$8$D$2$Check AnswerPlease select an answer for all 1 questions before checking your answers. 1 question remaining.2Real-World Problem
Question ExerciseIntermediateTeenager Scenario
If the length of a square's side is $\sqrt{x}$ meters and the area is 25 square meters, find $x$.Show AnswerClick to reveal the detailed solution for this question exercise.3Thinking Challenge
Thinking ExerciseIntermediateThink About This
Given $\sqrt{x+1} = x - 3$, solve for $x$.
Show AnswerClick to reveal the detailed explanation for this thinking exercise.4Challenge Quiz
Single Choice QuizAdvancedSolve $\sqrt{2x + 3} = x - 1$.
A$x = 2 + \sqrt{6}$B$x = 2 - \sqrt{6}$C$x = 1$D$x = 6$Check AnswerPlease select an answer for all 1 questions before checking your answers. 1 question remaining.Recap
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