Uint8_t & Uint16_t | B4X Programming Forum
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- Thread starter Siam
- Start date Jan 15, 2019
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Siam
Active Member
Licensed User Longtime User hello, how can i convert an uint to uint8_t or uint16_t in b4r ? i have the following command: B4X: getchar (c as uint8_t, size as uint_8t , buff as uint8_t) as uint8_t this funktion i will call B4X: uint8_t getChar(uint8_t c, uint8_t size, uint8_t *buf); this is in my .h file B4X: uint8_t getChar(uint8_t c, uint8_t size, uint8_t *buf); this is my .cpp file B4X: uint8_t B4RMDMAX72xxLedMatrix::getChar(uint8_t c, uint8_t size, uint8_t *buf){ return led->getChar(c, size, *buf); } how can i call this command ? regards Andy Last edited: Jan 15, 2019 If you like my work, you can offer me a coffee!
so you keep me motivated for more stuff like this. Sort by date Sort by votes Erel
B4X founder
Staff member Licensed User Longtime User uint8_t is the same as Byte. uint16_t is the same as UInt. [B4X] Features that Erel recommends to avoid [B4X] "Code Smells" - common mistakes and other tips Upvote 0Siam
Active Member
Licensed User Longtime User then i make something wrong
so you keep me motivated for more stuff like this. Upvote 0 Siam
Active Member
Licensed User Longtime User ok sometimes i should take a break ... now i have it thx If you like my work, you can offer me a coffee!
so you keep me motivated for more stuff like this. Upvote 0 You must log in or register to reply here. Similar Threads
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