When A Constant Force Is Applied To A Body It Moves Class 12 Physics ...

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seo-qnaheader left imagearrow-right Answerdown arrowQuestion Answers for Class 12down arrowClass 12 BiologyClass 12 ChemistryClass 12 EnglishClass 12 MathsClass 12 PhysicsClass 12 Social ScienceClass 12 Business StudiesClass 12 EconomicsQuestion Answers for Class 11down arrowClass 11 EconomicsClass 11 Computer ScienceClass 11 BiologyClass 11 ChemistryClass 11 EnglishClass 11 MathsClass 11 PhysicsClass 11 Social ScienceClass 11 AccountancyClass 11 Business StudiesQuestion Answers for Class 10down arrowClass 10 ScienceClass 10 EnglishClass 10 MathsClass 10 Social ScienceClass 10 General KnowledgeQuestion Answers for Class 9down arrowClass 9 General KnowledgeClass 9 ScienceClass 9 EnglishClass 9 MathsClass 9 Social ScienceQuestion Answers for Class 8down arrowClass 8 ScienceClass 8 EnglishClass 8 MathsClass 8 Social ScienceQuestion Answers for Class 7down arrowClass 7 ScienceClass 7 EnglishClass 7 MathsClass 7 Social ScienceQuestion Answers for Class 6down arrowClass 6 ScienceClass 6 EnglishClass 6 MathsClass 6 Social ScienceQuestion Answers for Class 5down arrowClass 5 ScienceClass 5 EnglishClass 5 MathsClass 5 Social ScienceQuestion Answers for Class 4down arrowClass 4 ScienceClass 4 EnglishClass 4 MathsSearchIconbannerWhen a constant force is applied to a body, it moves with uniform:A. AccelerationB. VelocityC. SpeedD. MomentumAnswerVerifiedVerified567.3k+ viewsHint: You could easily answer this question with the help of Newton’s second law of motion. You may recall that this law expresses force in terms of the given quantities in its various forms. Thus, you could see that which of these quantities would have been uniform if the force acting on the body was constant.Formula used:Newton’s second law,$F=\dfrac{dp}{dt}$Complete Step by step solution:In the question, we are said that a constant force is being applied to a body and we are asked to find which among the given quantities remains uniform in such a condition. In order to answer this let us recall Newton’s second law of motion, according to which time rate of change of linear momentum gives the force acting on a body. That is,$F=\dfrac{dp}{dt}$ ……………………………………………. (1)But we know that momentum is the product of mass and velocity and also for constant mass we get,$F=m\dfrac{dv}{dt}$ ……………………………………………….. (2)We know that the time rate of change of velocity is the object’s acceleration. So,$F=ma$ $\therefore a=\dfrac{F}{m}$ Thus, we see that acceleration is directly proportional to force and inversely proportional to object’s mass. Therefore, we could say that, for uniform force acting on a body of constant mass, acceleration would also uniform. Hence, option A is found to be the correct answer.Note: In case you're wondering about other quantities given in the question: speed, velocity and momentum, let us discuss them. From equation (1) we see that, time rate of change of momentum gives the force. So if the momentum had been uniform or constant, the force would have been zero. Similarly, from equation (2) we could directly conclude that constant velocity would have resulted in zero force on the body. Recently Updated PagesMaster Class 12 Economics: Engaging Questions & Answers for Successarrow-rightMaster Class 12 Physics: Engaging Questions & Answers for Successarrow-rightMaster Class 12 English: Engaging Questions & Answers for Successarrow-rightMaster Class 12 Social Science: Engaging Questions & Answers for Successarrow-rightMaster Class 12 Maths: Engaging Questions & Answers for Successarrow-rightMaster Class 12 Business Studies: Engaging Questions & Answers for Successarrow-rightMaster Class 12 Economics: Engaging Questions & Answers for Successarrow-rightMaster Class 12 Physics: Engaging Questions & Answers for Successarrow-rightMaster Class 12 English: Engaging Questions & Answers for Successarrow-rightMaster Class 12 Social Science: Engaging Questions & Answers for Successarrow-rightMaster Class 12 Maths: Engaging Questions & Answers for Successarrow-rightMaster Class 12 Business Studies: Engaging Questions & Answers for Successarrow-right
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