Which Of The Following Solutions Have The Lowest Osmotic Pressure ...

aarav5131 aarav5131

• 21.06.2018
• Chemistry
• Secondary School

answered • expert verified Which of the following solutions have the lowest osmotic pressure and why ? 1)0 1M NaCl 2) 0 1 M glucose 3) 0 1 M BaCl2 See answers aparnaappu8547 aparnaappu8547

Answer:

Glucose will have the lowest osmotic pressure because it has the lowest i value.

Explanation:

Osmotic pressure π = i×C×R×T

Where,

i       =       Van't Hoff factor

C = molar concentration of solute

R = ideal gas constant

T = temperature in Kelvin

In the given problem, C,R and T are same for all three solutions. Therefore we have to consider only i.

In case of NaCl, it dissociates into 2 ions.

NaCl →

⇒i = 2

In case of glucose, it is a covalent compound and thus will not dissociate into its respective ions.

⇒i = 1

In case of , it dissociates into 3 ions.

→

⇒i = 3

Since glucose has the lowest i, it will have the lowest osmotic pressure.

Aryendra Aryendra Osmotic pressure is equal to (i×C×R×T)Since C,R AND T are same for all we need to consider i here ,which is the vant Hoff factor. For NaCl it is 2 (as it dissociates into 2 ions )For glucose it is 1.For BaCl2 It is 3. Therfore glucose has the lowest osmotic pressure among all.

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