1) The PH Of An Aqueous Solution Of 0.283 M Tellurous Acid, H2TeO3 ...
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The pH of an aqueous solution of 0.283 M tellurous acid, H2TeO3 (aq), is . For H2TeO3, Ka1 = 5.40*10^-7 and Ka2 = 3.70*10^-9. The pH of an aqueous solution of 0.283 M tellurous acid, H2TeO3 (aq), is . For H2TeO3, Ka1 = 5.40*10^-7 and Ka2 = 3.70*10^-9.Added by James G.
Step 1
283 M tellurous acid solution. Since it's a diprotic acid, we'll consider the first ionization step: H2TeO3 (aq) <=> H+ (aq) + HTeO3- (aq) We can set up an ICE table for this reaction: Initial: [H2TeO3] = 0.283 M, [H+] = 0, [HTeO3-] = 0 Change: -x, +x, Show more…
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