2(3k + 1)x + 8k + 1 = 0 Has Equal Roots - Quadratic Equations - Toppr

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SolveGuidesJoin / LoginUse appLogin0You visited us 0 times! Enjoying our articles? Unlock Full Access!Standard XIIMathematicsNature of RootsQuestionFor what value/values of k: (k+1)x2−2(3k+1)x+8k+1=0 has equal roots Open in AppSolutionVerified by Toppr

Condition to have equal roots b2=4ac4(3k+1)2=4(k+1)(8k+1)9k2+6k+1=8k2+9k+1k2=3kk=0,3

Was this answer helpful?86Similar QuestionsQ1For what value/values of k: (k+1)x2−2(3k+1)x+8k+1=0 has equal roots View SolutionQ2The product of values of k for which the roots are real and equal of the following equation (k + 1)x2 - 2(3k + 1)x + 8k + 1 = 0 isView SolutionQ3Find the value of k for which the equation (k+1)x2−2(k−1)x+1=0 has real and equal rootsView SolutionQ4Find the values of k for which the roots are real and equal in each of the following equations: (i) kx2+4x+1=0 (ii) kx2-25x+4=0 (iii) 3x2-5x+2k=0 (iv) 4x2+kx+9=0 (v) 2kx2-40x+25=0 (vi) 9x2-24x+k=0 (vii) 4x2-3kx+1=0 (viii) x2-25+2kx+37+10k=0 (ix) 3k+1x2+2k+1x+k=0 (x) kx2+kx+1=-4x2-x (xi) k+1x2+2k+3x+k+8=0 (xii) x2-2kx+7k-12=0 (xiii) k+1x2-23k+1x+8k+1=0 (xiv) 2k+1x2+2k+3x+k+5=0 (xvii) 4x2-2k+1x+k+4=0 (xviii) 4x2-2k+1x+k+1=0

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