(2x²+x+1)-(x-1)(2x-3)/x-2 =7/2 - Math

kumarisumita29 kumarisumita29
  • 01.10.2018
  • Math
  • Secondary School
answered (2x²+x+1)-(x-1)(2x-3)/x-2 =7/2 See answers priyanshukumar3424 priyanshukumar3424 priyanshukumar3424

Step-by-step explanation:

The blue coloured part is cancelled

soniakulkarni soniakulkarni soniakulkarni (2x^2+x+1)-(2x^2-5x+3)=7x-14/2=>-4x-2=7x/2-7=>-4x-7x/2=2-7=>(-8x-7x)/2=-5=>-x/2=-5=>x/2=5=>x=10hope this will help you.

New questions in Math

what is value of pi step by step in math If a number is divisible by 18 and 2,it will be divisible by 36 also. Is it true or false? Factorise-a² +8a+16 The factorized form of the expression $a^2 + 8a + 16$ is $\mathbf{(a + 4)^2}$. ➡️ Step 1: Identify the quadratic pattern [1, 2] … The expression $a^2 + 8a + 16$ follows the form of a perfect square trinomial, which is defined by the algebraic identity: $x^2 + 2xy + y^2 = (x + y)^2$ ➡️ Step 2: Determine the values of x and y To apply the identity, we identify the square roots of the first and last terms: • The first term is $a^2$, so $x = a$. • The last term is $16$, which is $4^2$, so $y = 4$. [4, 5, 6, 7, 8] ➡️ Step 3: Verify the middle term [9] Check if the middle term matches $2xy$: $2(a)(4) = 8a$ Since the middle term matches exactly, we can rewrite the expression as: $a^2 + 2(a)(4) + 4^2$ ➡️ Step 4: Write the factored form Using the identity $(x + y)^2$, substitute $a$ for $x$ and $4$ for $y$: $(a + 4)^2$ ✅ Answer: The expression factorizes to (or ). [10] A circle of radius 10 is drawn with origin as centre. (i) Write the co-ordinates of a point at which this circle cuts the x-axis (ii) Check whether th … e point (5, 9) is inside, outside or on the circle. (iii) Write the equation of the circle.​ 1) Linear Functiont=2+py=x+12solve this equation and plot a graph ​ Previous Next

Từ khóa » (c) ((2x^(2)+x+1)-(x-1)(2x-3))/(x-2)=(7)/(2)