2x2-8x-12=0 - Solution

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2x2-8x-12=0

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Solution for 2x2-8x-12=0 equation:

2x^2-8x-12=0 a = 2; b = -8; c = -12;Δ = b2-4acΔ = -82-4·2·(-12)Δ = 160The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$The end solution: $\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$ $x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{10}}{2*2}=\frac{8-4\sqrt{10}}{4} $ $x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{10}}{2*2}=\frac{8+4\sqrt{10}}{4} $

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