A Compound With An Empirical Formula Of C2oh4 And A Molar Mass Of ...

Sangik32311 Sangik32311
  • 04.08.2019
  • Chemistry
  • Secondary School
answered • expert verified A compound with an empirical formula of c2oh4 and a molar mass of 88 grams per mole. Calculate its molecular formula. See answers qwmagpies qwmagpies qwmagpies

Given:The compound C_2OH_4 has a molar mass of 88.

Tofind:We have to find its molecular formula.

Solution:

The empirical formula of the compound is C_2OH_4.

The atomic mass of C is 12.

The atomic mass of Oxygen is 16 and the atomic mass of H is 1.

Thus the empirical mass of C_2OH_4 is

12 \times 2 + 16 + 4 \times 1 \\  = 24 + 16 + 4 \\  = 44

The empirical mass is 44.

The molar mass is 88.

Thus n value is 88/44=2.

The formula of the compound is (C_2OH_4)_2=C_4O_2H_8.

ThemolecularformulaofthecompoundisC_4O_2H_8.

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A compound with an empirical formula of C,OH, and a molar mass of 88 grams per mole. What is the molecular formula of this compound? ₂ OH₃ = 44,05 g/mol.

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