Answer Math Problems | Help With Math Problems - Math Only Math

Answer Math Problems

All grade answer math problems are solved here from different topics. A large number of objective answer math problems are solved here to help the students quickly to test their knowledge and skills on different topics.

1. Simplify: (4x2 - 2x) - (-5x2 - 8x). Solution: (4x2 - 2x) - (-5x2 - 8x) = 4x2 - 2x + 5x2 + 8x. = 4x2 + 5x2 - 2x + 8x. = 9x2 + 6x. = 3x(3x + 2). Answer: 3x(3x + 2) 2. Simplify: (-7x2 - 3x) - (4x2 - x) Solution: (-7x2 - 3x) - (4x2 - x) = -7x2 - 3x - 4x2 + x = -7x2 - 4x2 - 3x + x = -11x2 – 2x = -x(11x + 2) Answer: -x(11x + 2) 3. Simplify: (-5x2 - 8x + 7) - (5x2 - 4) Solution: (-5x2 - 8x + 7) - (5x2 - 4) = -5x2 - 8x + 7 - 5x2 + 4 = -5x2 - 5x2 - 8x + 7 + 4 = -10x2 – 8x + 11 Answer: -10x2 – 8x + 11 4. Simplify: (4x2 + 5x) + (x2 - 5x + 1) Solution: (4x2 + 5x) + (x2 - 5x + 1) = 4x2 + 5x + x2 - 5x + 1 = 4x2 + x2+ 5x - 5x + 1 = 5x2 + 0 + 1 = 5x2 + 1 Answer: 5x2 + 1 5. Simplify: (-6x + 3) - (-x2 + 5x) Solution: (-6x + 3) - (-x2 + 5x) = -6x + 3 + x2 - 5x = -6x - 5x + x2 + 3 = x2 – 11x + 3 Answer: x2 – 11x + 3 6. Simplify: (-9x - 5) - (-9x2 + x - 5) Solution: (-9x - 5) - (-9x2 + x - 5) = -9x - 5 + 9x2 - x + 5 = 9x2 - 9x – x – 5 + 5 = 9x2 – 10x = x(9x – 10) Answer: x(9x – 10)

7. Simplify: (2x - 4) - (6x + 6) Solution: (2x - 4) - (6x + 6) = 2x - 4 - 6x – 6 = 2x – 6x – 4 – 6 = -4x – 10 = -2(2x + 5) Answer: -2(2x + 5)8. Simplify:(8+4x)/4x Solution: (8+4x)/4x = 4(2 + x)/4x [Cancel 4 from the numerator and denominator] = (2 + x)/x Answer: (2 + x)/x9. Decide whether the lines are parallel, perpendicular or neither. x + 4y = 7 and 4x – y = 3 Solution: x + 4y = 7 4y = -x + 7 y = (-1/4) x + 7 Slope of the equation x + 4y = 7 is -1/4. Again, 4x – y = 3 y = 4x – 3 Slope of the equation 4x – y = 3 is 4. Since multiplying both the slope of the equation = -1/4 × 4 = -1 Therefore, the given two equations are perpendicular to each other. Answer: Perpendicular 10. Simplify: 3x – 5 + 23x – 9 Solution: 3x – 5 + 23x – 9 = 3x + 23x – 5 – 9 = 26x – 14 = 2(13x – 7) Answer: 2(13x – 7)

11. Use the discriminant to determine the number of real roots the equation has. 3x2 – 5x + 1 =0 (a) One real root (a double root), (b) Two distinct real roots, (c) Three real roots, (d) None (two imaginary roots) Solution: Discriminant = bx2 – 4ac Compare the above equation 3x2 – 5x + 1 =0 with ax2 + bx + c = 0 We get, a = 3, b = -5, c = 1 Put the value of a, b and c; Discriminant = bx2 – 4ac Discriminant = (-5)2 - 4 × 3 × 1 = 25 – 12 = 13 [13 > 0] Therefore, discriminant is positive. So the given equation has two distinct real roots. Answer: (b) 12. Use the discriminant to determine the number of real roots the equation has. 7x2 + 3x + 1 =0. (a) One real root (a double root),(b) Two distinct real roots,(c) Three real roots, (d) None (two imaginary roots) Solution: Discriminant = b2 – 4ac Compare the above equation 7x2 + 3x + 1 =0 with ax2 + bx + c = 0 We get, a = 7, b = 3, c = 1 Put the value of a, b and c; Discriminant = b2 – 4ac Discriminant = (3)2 - 4 × 7 × 1 = 9 – 28 = -19 [13 < 0] Therefore, discriminant is negative. So the given equation has none (two imaginary roots). Answer: (d)

13. Fill in the blank: (a) The point with coordinates (0,0) is called ........of a rectangular coordinate system. (b) To find the x-intercept of a line, we let....equal 0 and solve for ......; to find y-intercept, we let ......equal 0 and solve for....... Solution: (a) The point with coordinates (0,0) is called origin of a rectangular coordinate system. (b) To find the x-intercept of a line, we let y equal 0 and solve for x ; to find y-intercept, we let x equal 0 and solve for y .

14. Name the quadrant, if any, in which each point is located. (a) (1, 6) (b) (-4, -2) Solution: (a) (1, 6) --------- I Quadrant. (b) (-4, -2) --------- III Quadrant. If students have any queries understanding the questions and answers given in the answer math problems,  please fill-up the below comment box to convey your message, so that we can help you.

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