Answer To Question #96167 In General Chemistry For Brittany Wallace

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Q96167

Solution:

1. As the given equation is already balanced, using mole-mole analysis, we get:

"moles of KHP reacted = moles of NaOH reacted" -----(x)

"moles = given weight\/molecular weight"

thus, moles of KHP reacted = "0.4150g \/ 204.2g"

= 0.002 mol.

thus, "molarity = no. of moles used\/volume(in litres)" (for NaOH)

= "(0.002\/26.5)*1000"

= 0.075 M (Answer)

2. "moles = Molarity * Volume used (in litres)"

="0.098*14\/1000"

=1.372 milimoles.

hence, moles of NaOH used = 1.372 milimoles

hence, moles of KHP used = 1.372 milimoles (from (x))

"weight = moles*molecular weight"

Hence, weight of KHP used = "1.372*204.2\/1000"

= 0.28 gms.

"purity=weight used\/weight taken*100"

Thus, purity of KHP sample = "(0.28\/0.42)*100 %"

= 66.67% (Answer)

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