Answered: The Ethyl Acetate (CH3COOC2H5)… | Bartleby

Skip to main contentcloseHomework Help is Here – Start Your Trial Now!arrow_forwardSEARCHHomework help starts here!ASK AN EXPERTASKScienceChemistryThe ethyl acetate (CH3COOC2H5) concentration in an alcoholic solution was determined by diluting a 10.00-mL sample to 100.00 mL. A 20.00-mL aliquot of the diluted solution was refluxed with 40.00 mL of 0.04672 M KOH: ethyl acetate.JPG After cooling, the excess KOH was back-titrated with 3.85 mL of 0.04644 M H2SO4. Calculate the %(w/v) CH3COOC2H5 in the alcoholic solution.   MM CH3COOC2H5: 88.11 MM NaOH: 40.00 MM H2SO4: 98.08The ethyl acetate (CH3COOC2H5) concentration in an alcoholic solution was determined by diluting a 10.00-mL sample to 100.00 mL. A 20.00-mL aliquot of the diluted solution was refluxed with 40.00 mL of 0.04672 M KOH: ethyl acetate.JPG After cooling, the excess KOH was back-titrated with 3.85 mL of 0.04644 M H2SO4. Calculate the %(w/v) CH3COOC2H5 in the alcoholic solution.   MM CH3COOC2H5: 88.11 MM NaOH: 40.00 MM H2SO4: 98.08BUYAppl Of Ms Excel In Analytical Chemistry 2nd EditionISBN: 9781285686691Author: CrouchPublisher: Cengageexpand_less1 Excel Basics2 Basic Statistical Analysis With Excel3 Statistical Tests With Excel4 Least-squares And Calibration Methods5 Equilibrium, Activity And Solving Equations6 The Systematic Approach To Equilibria: Solving Many Equations7 Neutralization Titrations And Graphical Representations8 Polyfunctional Acids And Bases9 Complexometric And Precipitation Titrations10 Potentiometry And Redox Titrations11 Dynamic Electrochemistry12 Spectrochemical Methods13 Kinetic Methods14 Chromatography15 Electrophoresis And Other Separation Methods16 Data Processing With Excelexpand_moreChapter Questionsexpand_moreProblem 1PProblem 2PProblem 3PProblem 4PProblem 5PProblem 6PProblem 7PProblem 8PProblem 9PProblem 10Pformat_list_bulletedSee similar textbooks

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The ethyl acetate (CH3COOC2H5) concentration in an alcoholic solution was determined by diluting a 10.00-mL sample to 100.00 mL. A 20.00-mL aliquot of the diluted solution was refluxed with 40.00 mL of 0.04672 M KOH:

ethyl acetate.JPG

After cooling, the excess KOH was back-titrated with 3.85 mL of 0.04644 M H2SO4. Calculate the %(w/v) CH3COOC2H5 in the alcoholic solution.

 

MM CH3COOC2H5: 88.11

MM NaOH: 40.00

MM H2SO4: 98.08

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