Balance This Equation: C6H12O6 + O2→CO2 + H2O + Energy

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• Balance this equation C6H12O6 ...

AnswerQuestion Answers for Class 12Class 12 BiologyClass 12 ChemistryClass 12 EnglishClass 12 MathsClass 12 PhysicsClass 12 Social ScienceClass 12 Business StudiesClass 12 EconomicsQuestion Answers for Class 11Class 11 EconomicsClass 11 Computer ScienceClass 11 BiologyClass 11 ChemistryClass 11 EnglishClass 11 MathsClass 11 PhysicsClass 11 Social ScienceClass 11 AccountancyClass 11 Business StudiesQuestion Answers for Class 10Class 10 ScienceClass 10 EnglishClass 10 MathsClass 10 Social ScienceClass 10 General KnowledgeQuestion Answers for Class 9Class 9 General KnowledgeClass 9 ScienceClass 9 EnglishClass 9 MathsClass 9 Social ScienceQuestion Answers for Class 8Class 8 ScienceClass 8 EnglishClass 8 MathsClass 8 Social ScienceQuestion Answers for Class 7Class 7 ScienceClass 7 EnglishClass 7 MathsClass 7 Social ScienceQuestion Answers for Class 6Class 6 ScienceClass 6 EnglishClass 6 MathsClass 6 Social ScienceQuestion Answers for Class 5Class 5 ScienceClass 5 EnglishClass 5 MathsClass 5 Social ScienceQuestion Answers for Class 4Class 4 ScienceClass 4 EnglishClass 4 MathsBalance this equation: \[{{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{12}}}}{{\text{O}}_{\text{6}}}{\text{ + }}{{\text{O}}_{\text{2}}} \to {\text{C}}{{\text{O}}_{\text{2}}}{\text{ + }}{{\text{H}}_{\text{2}}}{\text{O + energy}}\]AnswerVerified554.4k+ viewsHint: Balancing a chemical equation includes the making of the number of atoms of each compound same on both sides of the arrow. Many methods can be used to do this to make the mass of any element at the beginning of a reaction equal to its mass at the end of the reaction.Complete step by step answer:A balanced chemical equation is essential for the calculation and study of various factors involved in a reaction. It can be achieved through making the number of elements of compounds on both sides of the arrow equal. Here we have the equation as follows;\[{{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{12}}}}{{\text{O}}_{\text{6}}}{\text{ + }}{{\text{O}}_{\text{2}}} \to {\text{C}}{{\text{O}}_{\text{2}}}{\text{ + }}{{\text{H}}_{\text{2}}}{\text{O + energy}}\]Here we are using the trial and error method.First, we are considering the number of carbon atoms in the reaction. Balancing its number, we can write the reaction as follows;\[{{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{12}}}}{{\text{O}}_{\text{6}}}{\text{ + }}{{\text{O}}_{\text{2}}} \to 6{\text{C}}{{\text{O}}_{\text{2}}}{\text{ + }}{{\text{H}}_{\text{2}}}{\text{O + energy}}\]Now the number of carbon atoms are same on both sides of the arrow. But the co-efficient 6 is applicable to all elements in \[{{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{12}}}}{{\text{O}}_{\text{6}}}\]. So now we are balancing the number of oxygen atoms and we get the equation as;\[{{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{12}}}}{{\text{O}}_{\text{6}}}{\text{ + 6}}{{\text{O}}_{\text{2}}} \to 6{\text{C}}{{\text{O}}_{\text{2}}}{\text{ + }}{{\text{H}}_{\text{2}}}{\text{O + energy}}\]The number of oxygen and hydrogen is not balanced on both sides and now we are adding a co-efficient to \[{{\text{H}}_{\text{2}}}{\text{O}}\] and then the equation becomes;\[{{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{12}}}}{{\text{O}}_{\text{6}}}{\text{ + 6}}{{\text{O}}_{\text{2}}} \to 6{\text{C}}{{\text{O}}_{\text{2}}}{\text{ + 6}}{{\text{H}}_{\text{2}}}{\text{O + energy}}\]Now we will analyse the number of each element on both sides of the reaction;${\text{Element}}\;{\text{ Reactant Side Product Side}} \\{\text{ C 6 6}} \\{\text{ H 12 12}} \\{\text{ O 18 18}} \\ $Hence the number of elements on both sides are now equal.Additional Information:The Law of Conservation of Mass dates was discovered in 1789 after Antoine Lavoisier discovered that mass can neither be created nor be destroyed in a chemical reaction and that the total mass of reactants and products will be the same at any point of time.Note: Balancing a chemical equation includes the use of law of conservation of mass which states that the mass of reactants reacted will be equal to the mass of products formed. It was discovered after Lavoisier’s theory of conservation of mass in chemical reactions.Recently Updated PagesMaster Class 12 Business Studies: Engaging Questions & Answers for SuccessMaster Class 12 Economics: Engaging Questions & Answers for SuccessMaster Class 12 English: Engaging Questions & Answers for SuccessMaster Class 12 Maths: Engaging Questions & Answers for SuccessMaster Class 12 Social Science: Engaging Questions & Answers for SuccessMaster Class 12 Chemistry: Engaging Questions & Answers for SuccessMaster Class 12 Business Studies: Engaging Questions & Answers for SuccessMaster Class 12 Economics: Engaging Questions & Answers for SuccessMaster Class 12 English: Engaging Questions & Answers for SuccessMaster Class 12 Maths: Engaging Questions & Answers for SuccessMaster Class 12 Social Science: Engaging Questions & Answers for SuccessMaster Class 12 Chemistry: Engaging Questions & Answers for Success

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