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1. A. Balance the following equation.

2 C6H14 + __ O2 → __ CO2 + __ H2O

            b. What type of reaction is this? _________________________________

c. How many grams of H2O are made from 45.6 g of O2?

d. How many liters of CO2 are produced from 389.44 L of O2?

e. How many grams of C6H14 are needed to make 87.10 mol of CO2?

f. How many moles of H2O are there if you start with 508.33 g of C6H14? 

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1 Expert Answer

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2C6H14 + 19O2 ==> 12CO2 + 14H2O ... balanced equation

b) Combustion reaction

c) 45.6 g O2 x 1 mol O2/32 g x 14 mol H2O / 19 mol H2O x 18 g H2O/mol H2O = 18.9 g H2O

d) 389.44 L O2 x 12 L CO2 / 19 L O2 = 245.96 L CO2

e) 87.10 mol CO2 x 2 mol C6H14 / 12 mol CO2 x 86 g C6H14/mol = 1248 g C6H14

f) 508.33 g C6H14 x 1 mol C6H14 / 86 g x 14 mol H2O / 2 mol C6H14 = 41.38 moles H2O

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