C2HNa + CH3I = C3H4 + INa - Chemical Equation Balancer

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Balanced Chemical Equation

C2HNa + CH3I → C3H4 + INa Reaction Info Balance Another Equation Step-by-Step Solution Practice Balancing

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Word Equation

Monosodium Acetylide + Methyl Iodide = Methylacetylene + Sodium Iodide

C2HNa + CH3I = C3H4 + INa is a Double Displacement (Metathesis) reaction where one mole of Monosodium Acetylide [C2HNa] and one mole of Methyl Iodide [CH3I] react to form one mole of Methylacetylene [C3H4] and one mole of Sodium Iodide [INa]

Reaction Type

Double Displacement (Metathesis)

Reactants

• Monosodium Acetylide - C2HNa

  C2HNa Molar Mass C2HNa Oxidation Number

• Methyl Iodide - CH3I

  Halon 10001 Iodomethane Ch3I Mei Monoiodomethane CH3I Molar Mass CH3I Oxidation Number

Products

• Methylacetylene - C3H4

  Methyl Acetylene Allylene Propine 1-Propyne Propyne C3H4 Molar Mass C3H4 Oxidation Number

• Sodium Iodide - INa

  Sodium Monoiodide Nai INa Molar Mass INa Bond Polarity INa Oxidation Number

Show Chemical Structure Image

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [C3H4] [INa] ) / ( [C2HNa] [CH3I] )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -(Δ[C2HNa] / Δt) = -(Δ[CH3I] / Δt) = (Δ[C3H4] / Δt) = (Δ[INa] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

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Examples

• Monosodium Acetylide + Methyl Iodide = Methylacetylene + Sodium Iodide
• C2HNa + CH3I = C3H4 + NaI
• COF3 = COF2 + F2
• BeO + Li2CO3 = Li2BeO2 + CO2
• CuO + N = Cu + NO2
• AgCl + KNO3 = AgCl + KNO3
• Cr2O3 + Cl2 = Cl3Cr + O2
• C6H5OH + K2Cr2O7 + H2SO4 = H2O + Cr2(SO4)3 + K2O4S + C6H4O2
• C7H5NaO2 + CH3Cl = C6H4COONaCH3 + HCl
• C6 + LiCoO2 = LiC6 + CoO2
• C2OH6 + O2 = CO2 + OH2
• ZnO + K2O4S = O4SZn + K2O
• KCIO3 + HCI = CI + KCI + H2O
• Recently Balanced Equations

Balance C2HNa + CH3I = C3H4 + INa Using the Algebraic Method

To balance the equation C2HNa + CH3I = C3H4 + INa using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a C2HNa + b CH3I = c C3H4 + d INa

Step 2: Create a System of Equations

Create an equation for each element (C, H, Na, I) where each term represents the number of atoms of the element in each reactant or product.

C: 2a + 1b = 3c + 0d H: 1a + 3b = 4c + 0d Na: 1a + 0b = 0c + 1d I: 0a + 1b = 0c + 1d

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination

• 2a + 1b - 3c = 0
• 1a + 3b - 4c = 0
• 1a - 1d = 0
• 1b - 1d = 0

Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 2 1 -3 0 0] [ 1 3 -4 0 0] [ 1 0 0 -1 0] [ 0 1 0 -1 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

• a = 1 (C2HNa)
• b = 1 (CH3I)
• c = 1 (C3H4)
• d = 1 (INa)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

C2HNa + CH3I = C3H4 + INa

Reactants	Products
C	3	3	✔️
H	4	4	✔️
Na	1	1	✔️
I	1	1	✔️

Since there is an equal number of each element in the reactants and products of C2HNa + CH3I = C3H4 + INa, the equation is balanced.

Balance C2HNa + CH3I = C3H4 + INa Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in C2HNa + CH3I = C3H4 + INa must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)			Products (Right Hand Side)
Reactants	Products
C2HNa	CH3I	Total	C3H4	INa	Total
C	2	1	3	3	3	✔️
H	1	3	4	4	4	✔️
Na	1	1	1	1	✔️
I	1	1	1	1	✔️

The number of atoms of each element on both sides of C2HNa + CH3I = C3H4 + INa is equal which means that the equation is already balanced and no additional work is needed.

Practice Balancing

C2HNa - + + CH3I - + = C3H4 - + + INa - +

Reactants	Products
C	3	3	✔️
H	4	4	✔️
Na	1	1	✔️
I	1	1	✔️

Hint: The sum of the balanced coefficients is 4. See Step-By-Step Solution

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