C3H8 + 5 O2 → 3 CO2 + 4 H2O | Wyzant Ask An Expert

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a. How many liters of propane(C3H8) will produce 5.67 liters of carbon dioxide? 

b. How many moles of propane are needed to produce 5.67 liters of carbon dioxide?

c. What mass of propane is needed to produce 5.67 liters of carbon dioxide?

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1 Expert Answer

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C3H8 + 5 O2 ==> 3 CO2 + 4 H2O ... balanced equation

Since we aren't given any conditions of temperature and pressure, we'll assume standard conditions (STP) which is

Temperature = 273K

Pressure = 1 atm

Also, at STP 1 mole of an ideal gas = 22.4 liters

Finally, for gases, moles and liters are equivalent so one can use the coefficients of the balanced equation.

a) 5.67 L CO2 x 1 L C3H8 / 3 L CO2 = 1.89 liters of C3H8

b) 1.89 L C3H8 x 1 mol / 22.4 L = 0.0844 moles C3H8

c) 0.0844 moles C3H8 x 44 g/mol = 3.71 g C3H8

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