C4H9OH + O2 CO2 + H2O For This Problem, Enter ... - Numerade
Question
Given the equation below for the combustion of butanol, set up the mole ratios of the following: C4H9OH + O2 CO2 + H2O For this problem, enter coefficients from the balanced chemical equation (do not reduce fractions) (b) H2O to O2 mol H2O mol O2 (c) CO2 to H2O mol CO2 mol H2O (d) C4H9OH to CO2 mol C4H9OH mol CO2 (e) H2O to C4H9OH mol H2O mol C4H9OH (f) CO2 to O2 mol CO2 mol O2 Given the equation below for the combustion of butanol, set up the mole ratios of the following: C4H9OH + O2 CO2 + H2O For this problem, enter coefficients from the balanced chemical equation (do not reduce fractions) (b) H2O to O2 mol H2O mol O2 (c) CO2 to H2O mol CO2 mol H2O (d) C4H9OH to CO2 mol C4H9OH mol CO2 (e) H2O to C4H9OH mol H2O mol C4H9OH (f) CO2 to O2 mol CO2 mol O2 Show more…Added by Diane G.
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Step 1: Determine the coefficients from the balanced chemical equation: C4H9OH + 6O2 -> 4CO2 + 5H2O Show more…
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During the combustion of butanol (C4H10O), what mass (in g) of butanol must be reacted to produce 67.1 g of products? N.B. Combustion is the reaction of a substance with molecular oxygen (O2) to produce water and carbon dioxide. (They didn't say which product is 67.1g, CO2 or H2O. They only said products, so the final product of everything after the combustion of butanol)
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And set up the mole ratio of (a.) O2 to C4H9OH (b.) H2O to O2 (c.) CO2 to H2O (d.) C4H9OH to CO2 (e.) H2O to C4H9OH (f.) CO2 to O2
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