C6H4(COOH)2 + Na = C6H4(COONa)2 + H2 - ChemicalAid

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Balanced Chemical Equation

C6H4(COOH)2 + 2Na → C6H4(COONa)2 + H2 Reaction Info Balance Another Equation Step-by-Step Solution Practice Balancing

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Word Equation

Phthalic Acid + Sodium = Disodium Terephthalate + Dihydrogen

C6H4(COOH)2 + Na = C6H4(COONa)2 + H2 is a Single Displacement (Substitution) reaction where one mole of Phthalic Acid [C6H4(COOH)2] and two moles of Sodium [Na] react to form one mole of Disodium Terephthalate [C6H4(COONa)2] and one mole of Dihydrogen [H2]

Reaction Type

Single Displacement (Substitution)

Reactants

• Phthalic Acid - C6H4(COOH)2

  O-Benzenedicarboxylate Alizarinate Sunftal 20 O-Carboxybenzoic Acid Phthalinate Phthalate Alizarinic Acid M 2 C6H4(COOH)2 Molar Mass C6H4(COOH)2 Oxidation Number

• Sodium - Na

  Natrium Element 11 Na Molar Mass Na Oxidation Number

Products

• Disodium Terephthalate - C6H4(COONa)2

  Sodium Benzene-1,4-Dicarboxylate Terephthalic Acid Disodium Salt Sodium Terephthalate C6H4(COONa)2 Molar Mass C6H4(COONa)2 Oxidation Number

• Dihydrogen - H2

  Molecular Hydrogen Hydrogen Molecule Hydrogen Hydrogen Gas Molecular Hydrogen Gas H₂ H2 Molar Mass H2 Bond Polarity H2 Oxidation Number

Show Chemical Structure Image

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [C6H4(COONa)2] [H2] ) / ( [C6H4(COOH)2] [Na]2 )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -(Δ[C6H4(COOH)2] / Δt) = -1/2 * (Δ[Na] / Δt) = (Δ[C6H4(COONa)2] / Δt) = (Δ[H2] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

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To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
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How To Balance Equations

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Examples

• Phthalic Acid + Sodium = Disodium Terephthalate + Dihydrogen
• CO(No3)2 + NH4OH = CO(OH)2 + NH4No3
• SO3 + Fe(OH)2 = FeO4S + H2O
• CH3CCH + Ag2O = CH3CCAg + H2O
• CH3CH2COH + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2O4S + CH3CH2COOH + H2O
• C2H2 + Cu2 = Cu2C2 + H2
• Mg + HI = MgI2H2
• TcO4{2-} + H2O = TcO4{-} + TcO2 + OH{-}
• K2CrO4 + HNO3 = CrH2O4 + KNO3
• C6H12N2O3 + NaOH = C2H6O + C2H4NNaO2
• CdCl2 + NH3 = Cd(Cl2(NH3)6)
• AgClO2 + Cl2 = AgCl + Cl2O + O2
• NO2 + KClO + KOH = KNO3 + H2O + KCl
• Recently Balanced Equations

Balance C6H4(COOH)2 + Na = C6H4(COONa)2 + H2 Using the Algebraic Method

To balance the equation C6H4(COOH)2 + Na = C6H4(COONa)2 + H2 using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a C6H4(COOH)2 + b Na = c C6H4(COONa)2 + d H2

Step 2: Create a System of Equations

Create an equation for each element (C, H, O, Na) where each term represents the number of atoms of the element in each reactant or product.

C: 8a + 0b = 8c + 0d H: 6a + 0b = 4c + 2d O: 4a + 0b = 4c + 0d Na: 0a + 1b = 2c + 0d

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination

• 8a - 8c = 0
• 6a - 4c - 2d = 0
• 4a - 4c = 0
• 1b - 2c = 0

Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 8 0 -8 0 0] [ 6 0 -4 -2 0] [ 4 0 -4 0 0] [ 0 1 -2 0 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

• a = 1 (C6H4(COOH)2)
• b = 2 (Na)
• c = 1 (C6H4(COONa)2)
• d = 1 (H2)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

C6H4(COOH)2 + 2 Na = C6H4(COONa)2 + H2

Reactants	Products
C	8	8	✔️
H	6	6	✔️
O	4	4	✔️
Na	2	2	✔️

Since there is an equal number of each element in the reactants and products of C6H4(COOH)2 + 2Na = C6H4(COONa)2 + H2, the equation is balanced.

Balance C6H4(COOH)2 + Na = C6H4(COONa)2 + H2 Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in C6H4(COOH)2 + Na = C6H4(COONa)2 + H2 must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)			Products (Right Hand Side)
Reactants	Products
C6H4(COOH)2	Na	Total	C6H4(COONa)2	H2	Total
C	8	8	8	8	✔️
H	6	6	4	2	6	✔️
O	4	4	4	4	✔️
Na	1	1	2	2	❌

Step 2: Multiply coefficients for compounds to balance out each element

For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your best judgement and be prepared to go back and try the other options.

1. Na is not balanced. Add 1 molecule of Na to the reactant (left-hand) side to balance Sodium: C6H4(COOH)2 + 2Na = C6H4(COONa)2 + H2

   Reactants	Products
   C	8	8	✔️
   H	6	6	✔️
   O	4	4	✔️
   Na	2	2	✔️

Step 3: Verify that the equation is balanced

Since there are an equal number of atoms of each element on both sides, the equation is balanced.

C6H4(COOH)2 + 2Na = C6H4(COONa)2 + H2

Practice Balancing

C6H4(COOH)2 - + + Na - + = C6H4(COONa)2 - + + H2 - +

Reactants	Products
C	8	8	✔️
H	6	6	✔️
O	4	4	✔️
Na	1	2	❌

Hint: The sum of the balanced coefficients is 5. See Step-By-Step Solution

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