C6H5CHOHCN = C6H5CHO + HCN - Chemical Equation Balancer

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Balanced Chemical Equation

C6H5CHOHCN → C6H5CHO + HCN Reaction Info Balance Another Equation Step-by-Step Solution Practice Balancing

Reaction Information Disclaimer

Word Equation

Oxindole = Benzaldehyde + Hydrogen Cyanide

C6H5CHOHCN = C6H5CHO + HCN is a Decomposition reaction where one mole of Oxindole [C6H5CHOHCN] decomposes into one mole of Benzaldehyde [C6H5CHO] and one mole of Hydrogen Cyanide [HCN]

Reaction Type

Decomposition

Reactants

  • Oxindole - C6H5CHOHCN

    3H-Indol-2-Ol Indolin-2-One 1,3-Dihydro-(2H)-Indol-2-One 2-Indolinone 1,3-Dihydroindol-2-One 2-Oxindole C6H5CHOHCN Molar Mass C6H5CHOHCN Oxidation Number

Products

  • Benzaldehyde - C6H5CHO

    Ben Benzoate Fema No. 2127 Oil Of Bitter Almond Benzyaldehyde Benzadehyde Benzoic Acid Almond Artificial Essential Oil C6H5CHO Molar Mass C6H5CHO Oxidation Number
  • Hydrogen Cyanide - HCN

    Methanenitrile Hcn [Chn] Prussic Acid Formonitrile Hydrocyanic Acid HCN Molar Mass HCN Oxidation Number
Show Chemical Structure Image

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [C6H5CHO] [HCN] ) / ( [C6H5CHOHCN] )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -(Δ[C6H5CHOHCN] / Δt) = (Δ[C6H5CHO] / Δt) = (Δ[HCN] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

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To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

  • Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
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  • Compound states [like (s) (aq) or (g)] are not required.
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Examples

  • Oxindole = Benzaldehyde + Hydrogen Cyanide
  • C6H5CHO + HCN = C6H5CH(OH)CN
  • Cl + HNO3 = ClHO3 + NO + H2O
  • ZnCl2 + MgO = ZnO + MgCl2
  • BaCl2 + Li = ClLi + Ba
  • KAl(SO4)2 + K2S + H2O = Al(OH)3 + H2S + K2O4S
  • NaMnO4 + SO2 + H2O = NaSO4 + MnSO4 + H2SO3
  • NaOH + ZnO = Na2O + H2O2Zn
  • Ba(NO2)2 + MnO2 + H2SO4 = MnSO4 + BaSO4 + HNO3 + H2O
  • Fe2(SO4)3 + BaSO4 = BaSO4 + Fe2(SO4)3
  • PBCO3 + HNO3 = PB(NO3)2 + CO2 + H2O
  • C6H4(COOC2H5)2 + H2O = C6H4(COOH)2 + C2H5OH
  • Al + Na2CO3 = Na + C3Al2O9
  • Recently Balanced Equations

Balance C6H5CHOHCN = C6H5CHO + HCN Using the Algebraic Method

To balance the equation C6H5CHOHCN = C6H5CHO + HCN using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a C6H5CHOHCN = b C6H5CHO + c HCN

Step 2: Create a System of Equations

Create an equation for each element (C, H, O, N) where each term represents the number of atoms of the element in each reactant or product.

C: 8a = 7b + 1c H: 7a = 6b + 1c O: 1a = 1b + 0c N: 1a = 0b + 1c

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination
  • 8a - 7b - 1c = 0
  • 7a - 6b - 1c = 0
  • 1a - 1b = 0
  • 1a - 1c = 0
Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 8 -7 -1 0] [ 7 -6 -1 0] [ 1 -1 0 0] [ 1 0 -1 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

  • a = 1 (C6H5CHOHCN)
  • b = 1 (C6H5CHO)
  • c = 1 (HCN)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

C6H5CHOHCN = C6H5CHO + HCN
Reactants Products
C88✔️
H77✔️
O11✔️
N11✔️
Since there is an equal number of each element in the reactants and products of C6H5CHOHCN = C6H5CHO + HCN, the equation is balanced.

Balance C6H5CHOHCN = C6H5CHO + HCN Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in C6H5CHOHCN = C6H5CHO + HCN must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)Products (Right Hand Side)
ReactantsProducts
C6H5CHOHCNTotalC6H5CHOHCNTotal
C88718✔️
H77617✔️
O1111✔️
N1111✔️

The number of atoms of each element on both sides of C6H5CHOHCN = C6H5CHO + HCN is equal which means that the equation is already balanced and no additional work is needed.

Practice Balancing

C6H5CHOHCN - + = C6H5CHO - + + HCN - +
ReactantsProducts
C88✔️
H77✔️
O11✔️
N11✔️
Hint: The sum of the balanced coefficients is 3. See Step-By-Step Solution

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