C6H5cOOH ->[(i) NH3][(ii) Δ] P ->[NaOBr] Q - Tardigrade App
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- C6H5cOOH xrightarrow[(ii) Δ] (i) NH3P xrightarrowNaOBrQ xrightarrow[(ii) textHeat to 460 K](i) Conc.H2SO4R 'R' is
sulphanilamide
16% B-bromosulphanilamide
35% C-bromosulphanilic acid
20% Dsulphanilic acid
29%Solution:
Correct answer is (d) sulphanilic acid
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