C6H5COOH+O2 = CO2+H2O | Wyzant Ask An Expert

Subject ZIP Search Search Find an Online Tutor Now Ask Ask a Question For Free Login Chemistry C6H5COOH+O2 = CO2+H2O Balance the chemical formula Follow • 4 Add comment More Report

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Best Newest Oldest By: Best Newest Oldest Lets start from: C6H5COOH + O2 = CO2 + H2O or re-write as C7H6O2 + O2 = CO2 + H2O Left side: 7C, 6H, 4(O) Right side: 1C, 2H, 3(O) Balance the carbons on both side: C7H6O2 + O2 = 7CO2 + H2O Left side: 7C, 6H, 4(O)Right side: 7C, 2H, 15(O) Next balance the hydrogen: C7H6O2 + O2 = 7CO2 + 3H2O Left side: 7C, 6H, 4(O)Right side: 7C, 6H, 17(O) What is left is balancing the Oxygen, leave the O in C7H6O2 alone and work on O2: C7H6O2 + (15/2)O2 = 7CO2 + 3H2O, the equation is balanced as is but we need coefficients to be whole numbers. Multiply both sides by 2 and you get your final answer as: 2C7H6O2 + 15O2 = 14CO2 + 6H2O Left side: 14C, 12H, 34(O)Right side: 14C, 12H, 34(O) %MCEPASTEBIN% Upvote • 0 Downvote Add comment More Report You should first condense the formula so that all representative atoms are combined: C7H6O2 + O2 = CO2 + H2O as can be seen, they are not balanced Left Side of Equation Atom Right Side of Equation 7 C 1 6 H 2 4 O 3 (*note that they can be added together as long as they are in the same side) While the most striking imbalance belongs to Carbon, place the whole numbers before the formula on the right C7H6O2 + O2 = 7CO2 + H2O (C=7, H=6, O=4) (C=7, H=2, O=15) Next is balance out Hydrogen C7H6O2 + O2 = 7CO2 + 3H2O (C=7,H=6,O=4) = (C=7, H=6, O=17) Since oxygen is still unbalanced, try to find a number that can satisfy both sides of the equation, i.e. you need 15 more atoms of Oxygen since 2 Oxygen atoms are already present in the carboxylic acid; thus you are left to manipulate only the free O2 C7H6O2 + (15/2)O2 = 7CO2 + 3H2O (C=7,H=6,O=17) = (C=7,H=6,O=17) and since it requires all whole numbers simply multiply the whole equation by the denominator (which is 2) giving you: 2C7H6O2 + 15O2 = 14CO2 + 6 H2O (C=14,H=12,O=34) = (C=14,H=12,O=34) Upvote • 0 Downvote Add comment More Report Let's start with the Carbons. There are 6 on the left and 1 on the right. Therefore, we need to put a 6 in front of the CO2 term to get 6 carbons on the right. C6H5COOH + O2 ---> 6 CO2 + H2O Now for the Hydrogens. There are 6 on the left and 2 on the right. We need to put a 3 in front of the H2O term to get 6 hydrogens on the right. C6H5COOH + O2 ---> 6 CO2 + 3 H2O Now, on the right, we have 6 carbons, 6 hydrogens and 15 oxygens. On the left, we have 4 oxygens. We need to get 15 oxygens on the left. If we count the 2 oxygens in the C6H5COOH as 2 of our 15, then we have 13 oxygens to get from the O2 term. Therefore, we need (13/2) O2 molecules. C6H5COOH + (13/2) O2 ---> 6 CO2 + 3 H2O To get rid of the fraction in front of the O2 term, multiply everything by 2. 2 C6H5COOH + 13 O2 ---> 12 CO2 + 6 H2O The equation should now be balanced. We can check: Right: 12 carbons, 12 hydrogens, 30 oxygens Left: 12 carbons, 12 hydrogens, 30 oxygens Upvote • 0 Downvote Add comment More Report

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