C6H5NH(COCH3) + Br2 + CH3COOH = C8H8BrNO + HBr

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Balanced Chemical Equation

C6H5NH(COCH3) + Br2 + 0CH3COOH → C8H8BrNO + HBr

Warning: Some compounds do not play a role in the reaction and have 0 coefficients. Make sure you have entered the equation properly.

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Word Equation

Acetanilide + Dibromine + Acetic Acid = P-Bromoacetanilide + Hydrogen Bromide

One mole of Acetanilide [C6H5NH(COCH3)], one mole of Dibromine [Br2] and zero moles of Acetic Acid [CH3COOH] react to form one mole of P-Bromoacetanilide [C8H8BrNO] and one mole of Hydrogen Bromide [HBr]

Reactants

• Acetanilide - C6H5NH(COCH3)

  N-Acetylarylamine C6H5NH(COCH3) Molar Mass C6H5NH(COCH3) Oxidation Number

• Dibromine - Br2

  Bromine Gas Bromine Liquid Bromine Br₂ Br2 Molar Mass Br2 Bond Polarity Br2 Oxidation Number

• Acetic Acid - CH3COOH

  Ch3Cooh E260 Ethanoat Ethanoic Acid Aceticum Acidum Methanecarboxylic Acid Ethoic Acid Ethylic Acid CH3COOH Molar Mass CH3COOH Oxidation Number

Products

• P-Bromoacetanilide - C8H8BrNO

  N-(4-Bromophenil)Ethanamide

• Hydrogen Bromide - HBr

  Hbr HBr Molar Mass HBr Bond Polarity HBr Oxidation Number

Show Chemical Structure Image

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [C8H8BrNO] [HBr] ) / ( [C6H5NH(COCH3)] [Br2] [CH3COOH]0 )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -(Δ[C6H5NH(COCH3)] / Δt) = -(Δ[Br2] / Δt) = 1/0 * (Δ[CH3COOH] / Δt) = (Δ[C8H8BrNO] / Δt) = (Δ[HBr] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
• Ionic charges are not yet supported and will be ignored.
• Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
• Compound states [like (s) (aq) or (g)] are not required.
• You can use parenthesis () or brackets [].

How To Balance Equations

Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured.

Read our article on how to balance chemical equations or ask for help in our chat.

Examples

• Acetanilide + Dibromine + Acetic Acid = P-Bromoacetanilide + Hydrogen Bromide
• BaOHNO3 = Ba + O + H + N + O
• Na2HPO4 + NH3 = Na3O4P + H12N3O4P
• C4H9Cl + Br2 = C4H9Cl(Br2)
• AgNO3 + HF = HNO3 + AgF
• BaCl2 + Ca(OH)2 = BaH2O2 + CaCl2
• CH3CHCHCH3 + KMnO4 + H2O = (CH3)2C2O4 + MnO2 + KOH
• FeCl2 + Al(OH)3 = FeCl2 + Al(OH)3
• NaBr + AgNo3 = NaNo3 + AgBr
• Al + S = Al6 + S3
• KHS + H2O2 = KOH + S + H2
• Mg(MnO4)2 + H2SO3 = MgSO4 + H2SO4 + MnSO4 + H2O
• SNCl4 + Na2S = SNS2 + NaCl
• Recently Balanced Equations

Balance C6H5NH(COCH3) + Br2 + CH3COOH = C8H8BrNO + HBr Using the Algebraic Method

To balance the equation C6H5NH(COCH3) + Br2 + CH3COOH = C8H8BrNO + HBr using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a C6H5NH(COCH3) + b Br2 + c CH3COOH = d C8H8BrNO + f HBr

Step 2: Create a System of Equations

Create an equation for each element (C, H, N, O, Br) where each term represents the number of atoms of the element in each reactant or product.

C: 8a + 0b + 2c = 8d + 0f H: 9a + 0b + 4c = 8d + 1f N: 1a + 0b + 0c = 1d + 0f O: 1a + 0b + 2c = 1d + 0f Br: 0a + 2b + 0c = 1d + 1f

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination

• 8a + 2c - 8d = 0
• 9a + 4c - 8d - 1f = 0
• 1a - 1d = 0
• 1a + 2c - 1d = 0
• 2b - 1d - 1f = 0

Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 8 0 2 -8 0 0] [ 9 0 4 -8 -1 0] [ 1 0 0 -1 0 0] [ 1 0 2 -1 0 0] [ 0 2 0 -1 -1 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

• a = 1 (C6H5NH(COCH3))
• b = 1 (Br2)
• c = 0 (CH3COOH)
• d = 1 (C8H8BrNO)
• f = 1 (HBr)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

C6H5NH(COCH3) + Br2 + 0 CH3COOH = C8H8BrNO + HBr

Reactants	Products
C	8	8	✔️
H	9	9	✔️
N	1	1	✔️
O	1	1	✔️
Br	2	2	✔️

Since there is an equal number of each element in the reactants and products of C6H5NH(COCH3) + Br2 + 0CH3COOH = C8H8BrNO + HBr, the equation is balanced.

Balance C6H5NH(COCH3) + Br2 + CH3COOH = C8H8BrNO + HBr Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in C6H5NH(COCH3) + Br2 + CH3COOH = C8H8BrNO + HBr must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)				Products (Right Hand Side)
Reactants	Products
C6H5NH(COCH3)	Br2	CH3COOH	Total	C8H8BrNO	HBr	Total
C	8	2	10	8	8	❌
H	9	4	13	8	1	9	❌
N	1	1	1	1	✔️
O	1	2	3	1	1	❌
Br	2	2	1	1	2	✔️

Step 2: Multiply coefficients for compounds to balance out each element

For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your best judgement and be prepared to go back and try the other options.

We could not determine all the steps needed to balance the equation using trial and error. This may mean it requires too many steps and the chemical equation is too complex to use this method, or that the equation is invalid (e.g. has 0 or non-integer coefficients). The algebraic method is likely better suited for balancing this equation.

If you would like to attempt to guess the next steps, the final element counts in the balanced equation should be:

C6H5NH(COCH3) + Br2 + 0CH3COOH = C8H8BrNO + HBr

Reactants	Products
C	8	8	✔️
H	9	9	✔️
N	1	1	✔️
O	1	1	✔️
Br	2	2	✔️

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