C6H5OC2H5 + HBr = C6H5OH + C2H5Br - Chemical Equation ...

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Balanced Chemical Equation

C6H5OC2H5 + HBr → C6H5OH + C2H5Br Reaction Info Balance Another Equation Step-by-Step Solution Practice Balancing

Reaction Information Disclaimer

Word Equation

Phenylethyl Alcohol + Hydrogen Bromide = Phenol + Bromoethane

One mole of Phenylethyl Alcohol [C6H5OC2H5] and one mole of Hydrogen Bromide [HBr] react to form one mole of Phenol [C6H5OH] and one mole of Bromoethane [C2H5Br]

Reactants

• Phenylethyl Alcohol - C6H5OC2H5

  Phenyl Ethyl Alcohol 2-Phenyiethanol Benzyl-Methanol Hydroxyethylbenzene Benzeneethanol, 9Ci Phenylethanol 2-Phenylethan-1-Ol Beta -Hydroxyethylbenzene C6H5OC2H5 Molar Mass C6H5OC2H5 Oxidation Number

• Hydrogen Bromide - HBr

  Hbr HBr Molar Mass HBr Bond Polarity HBr Oxidation Number

Products

• Phenol - C6H5OH

  Campho-Phenique Gel Phenol Homopolymer Phenol Polymer-Bound Synthetic Phenol Carbolic Oil Monophenol Tea Polyphenol Izal C6H5OH Molar Mass C6H5OH Oxidation Number

• Bromoethane - C2H5Br

  Monobromoethane Ethyl Bromide C2H5Br Molar Mass C2H5Br Oxidation Number

Show Chemical Structure Image

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [C6H5OH] [C2H5Br] ) / ( [C6H5OC2H5] [HBr] )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -(Δ[C6H5OC2H5] / Δt) = -(Δ[HBr] / Δt) = (Δ[C6H5OH] / Δt) = (Δ[C2H5Br] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
• Ionic charges are not yet supported and will be ignored.
• Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
• Compound states [like (s) (aq) or (g)] are not required.
• You can use parenthesis () or brackets [].

How To Balance Equations

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Examples

• Phenylethyl Alcohol + Hydrogen Bromide = Phenol + Bromoethane
• C6H5OC2H5 + HBr = C6HOC2Br + H2
• C6H5OH + C2H5Br = C6H5OC2H5 + HBr
• Li2Co3 = Li + Co3
• COF3 = COF2 + F2
• C2H5Cl + C6H5 = C7H8 + HCl
• K2Cr2O7 + Na2SO3 + H2SO4 = Cr2O3 + K2O4S + Na2SO4 + H2O
• K{+} + (ClO4){-} = KClO4
• KCl + Na2SO4 = KCl + Na2SO4
• CUCl2 + NH3 = (CU(NH3)4)Cl2
• Al + H3Po4 = AlPo4 + H2
• HCl + SO2 = Cl2 + H2SO2
• (CU(Nh3)2)Cl + AgNo3 = (CU(Nh3)2)Ag + ClNo3
• Recently Balanced Equations

Balance C6H5OC2H5 + HBr = C6H5OH + C2H5Br Using the Algebraic Method

To balance the equation C6H5OC2H5 + HBr = C6H5OH + C2H5Br using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a C6H5OC2H5 + b HBr = c C6H5OH + d C2H5Br

Step 2: Create a System of Equations

Create an equation for each element (C, H, O, Br) where each term represents the number of atoms of the element in each reactant or product.

C: 8a + 0b = 6c + 2d H: 10a + 1b = 6c + 5d O: 1a + 0b = 1c + 0d Br: 0a + 1b = 0c + 1d

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination

• 8a - 6c - 2d = 0
• 10a + 1b - 6c - 5d = 0
• 1a - 1c = 0
• 1b - 1d = 0

Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 8 0 -6 -2 0] [ 10 1 -6 -5 0] [ 1 0 -1 0 0] [ 0 1 0 -1 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

• a = 1 (C6H5OC2H5)
• b = 1 (HBr)
• c = 1 (C6H5OH)
• d = 1 (C2H5Br)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

C6H5OC2H5 + HBr = C6H5OH + C2H5Br

Reactants	Products
C	8	8	✔️
H	11	11	✔️
O	1	1	✔️
Br	1	1	✔️

Since there is an equal number of each element in the reactants and products of C6H5OC2H5 + HBr = C6H5OH + C2H5Br, the equation is balanced.

Balance C6H5OC2H5 + HBr = C6H5OH + C2H5Br Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in C6H5OC2H5 + HBr = C6H5OH + C2H5Br must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)			Products (Right Hand Side)
Reactants	Products
C6H5OC2H5	HBr	Total	C6H5OH	C2H5Br	Total
C	8	8	6	2	8	✔️
H	10	1	11	6	5	11	✔️
O	1	1	1	1	✔️
Br	1	1	1	1	✔️

The number of atoms of each element on both sides of C6H5OC2H5 + HBr = C6H5OH + C2H5Br is equal which means that the equation is already balanced and no additional work is needed.

Practice Balancing

C6H5OC2H5 - + + HBr - + = C6H5OH - + + C2H5Br - +

Reactants	Products
C	8	8	✔️
H	11	11	✔️
O	1	1	✔️
Br	1	1	✔️

Hint: The sum of the balanced coefficients is 4. See Step-By-Step Solution

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