C6H5ONa + C3H7Cl = C6H5OC3H7 + NaCl - Chemical Equation ...

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Balanced Chemical Equation

C6H5ONa + C3H7Cl → C6H5OC3H7 + NaCl Reaction Info Balance Another Equation Step-by-Step Solution Practice Balancing

Reaction Information Disclaimer

Word Equation

Phenolate Sodium + Propyl Chloride = P-Isopropylphenol + Sodium Chloride

C6H5ONa + C3H7Cl = C6H5OC3H7 + NaCl is a Double Displacement (Metathesis) reaction where one mole of Phenolate Sodium [C6H5ONa] and one mole of Propyl Chloride [C3H7Cl] react to form one mole of P-Isopropylphenol [C6H5OC3H7] and one mole of Sodium Chloride [NaCl]

Reaction Type

Double Displacement (Metathesis)

Reactants

• Phenolate Sodium - C6H5ONa

  Sodium Carbolate Sodium Phenate Sodium Phenoxide C6H5ONa Molar Mass C6H5ONa Oxidation Number

• Propyl Chloride - C3H7Cl

  1-Propyl Chloride Chloromethylethane 1-Chloropropane C3H7Cl Molar Mass C3H7Cl Oxidation Number

Products

• P-Isopropylphenol - C6H5OC3H7

  C6H5OC3H7 Molar Mass C6H5OC3H7 Oxidation Number

• Sodium Chloride - NaCl

  Broncho Saline Nacl Common Salt Table Salt Salt NaCl Molar Mass NaCl Bond Polarity NaCl Oxidation Number

Show Chemical Structure Image

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [C6H5OC3H7] [NaCl] ) / ( [C6H5ONa] [C3H7Cl] )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -(Δ[C6H5ONa] / Δt) = -(Δ[C3H7Cl] / Δt) = (Δ[C6H5OC3H7] / Δt) = (Δ[NaCl] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

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Examples

• Phenolate Sodium + Propyl Chloride = P-Isopropylphenol + Sodium Chloride
• SO3 + SiO2 = SiO + SO4
• K2Cr2O7 + Na2SO3 + H2SO4 = Cr2O3 + K2O4S + Na2SO4 + H2O
• Cl2O + K2O = ClKO
• Li2Co3 = Li + Co3
• CUCl2 + NH3 = (CU(NH3)4)Cl2
• C2H5Cl + C6H5 = C7H8 + HCl
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• (CU(Nh3)2)Cl + AgNo3 = (CU(Nh3)2)Ag + ClNo3
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Balance C6H5ONa + C3H7Cl = C6H5OC3H7 + NaCl Using the Algebraic Method

To balance the equation C6H5ONa + C3H7Cl = C6H5OC3H7 + NaCl using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a C6H5ONa + b C3H7Cl = c C6H5OC3H7 + d NaCl

Step 2: Create a System of Equations

Create an equation for each element (C, H, O, Na, Cl) where each term represents the number of atoms of the element in each reactant or product.

C: 6a + 3b = 9c + 0d H: 5a + 7b = 12c + 0d O: 1a + 0b = 1c + 0d Na: 1a + 0b = 0c + 1d Cl: 0a + 1b = 0c + 1d

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination

• 6a + 3b - 9c = 0
• 5a + 7b - 12c = 0
• 1a - 1c = 0
• 1a - 1d = 0
• 1b - 1d = 0

Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 6 3 -9 0 0] [ 5 7 -12 0 0] [ 1 0 -1 0 0] [ 1 0 0 -1 0] [ 0 1 0 -1 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

• a = 1 (C6H5ONa)
• b = 1 (C3H7Cl)
• c = 1 (C6H5OC3H7)
• d = 1 (NaCl)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

C6H5ONa + C3H7Cl = C6H5OC3H7 + NaCl

Reactants	Products
C	9	9	✔️
H	12	12	✔️
O	1	1	✔️
Na	1	1	✔️
Cl	1	1	✔️

Since there is an equal number of each element in the reactants and products of C6H5ONa + C3H7Cl = C6H5OC3H7 + NaCl, the equation is balanced.

Balance C6H5ONa + C3H7Cl = C6H5OC3H7 + NaCl Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in C6H5ONa + C3H7Cl = C6H5OC3H7 + NaCl must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)			Products (Right Hand Side)
Reactants	Products
C6H5ONa	C3H7Cl	Total	C6H5OC3H7	NaCl	Total
C	6	3	9	9	9	✔️
H	5	7	12	12	12	✔️
O	1	1	1	1	✔️
Na	1	1	1	1	✔️
Cl	1	1	1	1	✔️

The number of atoms of each element on both sides of C6H5ONa + C3H7Cl = C6H5OC3H7 + NaCl is equal which means that the equation is already balanced and no additional work is needed.

Practice Balancing

C6H5ONa - + + C3H7Cl - + = C6H5OC3H7 - + + NaCl - +

Reactants	Products
C	9	9	✔️
H	12	12	✔️
O	1	1	✔️
Na	1	1	✔️
Cl	1	1	✔️

Hint: The sum of the balanced coefficients is 4. See Step-By-Step Solution

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