C6H8O6 + C6H9I2NO + H2O = C6H10O5 + I2O5 + N2O2

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Balanced Chemical Equation

19C6H8O6 + 4C6H9I2NO + 21H2O → 23C6H10O5 + 4I2O5 + 2N2O2 Reaction Info Balance Another Equation Step-by-Step Solution Practice Balancing

Reaction Information Disclaimer

Word Equation

Vitamin C + Povidone-Iodine + Water = Meglutol + Iodine Pentoxide + Dioxohydrazine

Nineteen moles of Vitamin C [C6H8O6], four moles of Povidone-Iodine [C6H9I2NO] and twenty-one moles of Water [H2O] react to form twenty-three moles of Meglutol [C6H10O5], four moles of Iodine Pentoxide [I2O5] and two moles of Dioxohydrazine [N2O2]

Reactants

• Vitamin C - C6H8O6

  Ovc307 L-Ascorbic Acid Cevex Ascoltin Cecon Cenolate Cebione Cetane C6H8O6 Molar Mass C6H8O6 Oxidation Number

• Povidone-Iodine - C6H9I2NO

  Pvp-I Povidone Iodine E-Z Scrub E-Z Prep E-Z Scrub 241 Betadine E-Z Scrub 201 E-Z Prep 220

• Water - H2O

  Hydroxic Acid H₂O [Oh2] Aqua Pure Water Hydrogen Oxide Oxidane Dihydrogen Oxide H2O Molar Mass H2O Oxidation Number

Products

• Meglutol - C6H10O5

  3-Hydroxy-3-Methyl-Glutaric Acid 3-Methyl-3-Hydroxyglutaric Acid Cb 337 3-Hydroxymethylglutarate B-Hydroxy-B-Methylglutaric Acid Dicrotalate B-Hydroxy-B-Methylglutarate 3-Methyl-3-Hydroxyglutarate C6H10O5 Molar Mass C6H10O5 Oxidation Number

• Iodine Pentoxide - I2O5

  Diiodine Pentoxide Iodine(V) Oxide O2Ioio2 I2O5 Molar Mass I2O5 Oxidation Number

• Dioxohydrazine - N2O2

  Dinitrogen Dioxide Onno N2O2 Molar Mass N2O2 Oxidation Number

Show Chemical Structure Image

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [C6H10O5]23 [I2O5]4 [N2O2]2 ) / ( [C6H8O6]19 [C6H9I2NO]4 [H2O]21 )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -1/19 * (Δ[C6H8O6] / Δt) = -1/4 * (Δ[C6H9I2NO] / Δt) = -1/21 * (Δ[H2O] / Δt) = 1/23 * (Δ[C6H10O5] / Δt) = 1/4 * (Δ[I2O5] / Δt) = 1/2 * (Δ[N2O2] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
• Ionic charges are not yet supported and will be ignored.
• Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
• Compound states [like (s) (aq) or (g)] are not required.
• You can use parenthesis () or brackets [].

How To Balance Equations

Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured.

Read our article on how to balance chemical equations or ask for help in our chat.

Examples

• Vitamin C + Povidone-Iodine + Water = Meglutol + Iodine Pentoxide + Dioxohydrazine
• C6H8O6 + C6H9I2NO + H2O = C6H10O5 + IO + N2O20
• FeCl2 + SiO2 = FeCl2O2 + Si
• PH3 + KMnO4 = MnO2 + K3PO4 + K2HPO4 + H2O
• Sn(OH)2 + Mg(OH)2 = Mg(Sn(OH)4)
• Ca(AlO2)2 + HNo3 = Al(No3)3 + Ca(No3)2 + H2O
• Ba + H3Po4 = Ba3(Po4)2 + H2
• Mg(OH)2 + NH4Cl + Na2HPO4 = MgCl2 + H12N3O4P + NaOH + H2O
• Na3PO4 + NaOH = NaPO4 + Na3OH
• BaBr2 + CO = CO + BaBr2
• KF + HNO3 = KNO3 + FH
• AlCl3 + NaOH = Al + OH + NaCl
• (2Ca) + O2 = (2CaO)
• Recently Balanced Equations

Balance C6H8O6 + C6H9I2NO + H2O = C6H10O5 + I2O5 + N2O2 Using the Algebraic Method

To balance the equation C6H8O6 + C6H9I2NO + H2O = C6H10O5 + I2O5 + N2O2 using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a C6H8O6 + b C6H9I2NO + c H2O = d C6H10O5 + f I2O5 + g N2O2

Step 2: Create a System of Equations

Create an equation for each element (C, H, O, I, N) where each term represents the number of atoms of the element in each reactant or product.

C: 6a + 6b + 0c = 6d + 0f + 0g H: 8a + 9b + 2c = 10d + 0f + 0g O: 6a + 1b + 1c = 5d + 5f + 2g I: 0a + 2b + 0c = 0d + 2f + 0g N: 0a + 1b + 0c = 0d + 0f + 2g

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination

• 6a + 6b - 6d = 0
• 8a + 9b + 2c - 10d = 0
• 6a + 1b + 1c - 5d - 5f - 2g = 0
• 2b - 2f = 0
• 1b - 2g = 0

Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 6 6 0 -6 0 0 0] [ 8 9 2 -10 0 0 0] [ 6 1 1 -5 -5 -2 0] [ 0 2 0 0 -2 0 0] [ 0 1 0 0 0 -2 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

• a = 19 (C6H8O6)
• b = 4 (C6H9I2NO)
• c = 21 (H2O)
• d = 23 (C6H10O5)
• f = 4 (I2O5)
• g = 2 (N2O2)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

19 C6H8O6 + 4 C6H9I2NO + 21 H2O = 23 C6H10O5 + 4 I2O5 + 2 N2O2

Reactants	Products
C	138	138	✔️
H	230	230	✔️
O	139	139	✔️
I	8	8	✔️
N	4	4	✔️

Since there is an equal number of each element in the reactants and products of 19C6H8O6 + 4C6H9I2NO + 21H2O = 23C6H10O5 + 4I2O5 + 2N2O2, the equation is balanced.

Balance C6H8O6 + C6H9I2NO + H2O = C6H10O5 + I2O5 + N2O2 Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in C6H8O6 + C6H9I2NO + H2O = C6H10O5 + I2O5 + N2O2 must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)				Products (Right Hand Side)
Reactants	Products
C6H8O6	C6H9I2NO	H2O	Total	C6H10O5	I2O5	N2O2	Total
C	6	6	12	6	6	❌
H	8	9	2	19	10	10	❌
O	6	1	1	8	5	5	2	12	❌
I	2	2	2	2	✔️
N	1	1	2	2	❌

Step 2: Multiply coefficients for compounds to balance out each element

For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your best judgement and be prepared to go back and try the other options.

1. C is not balanced. Add 1 molecule of C6H10O5 to the product (right-hand) side to balance Carbon: C6H8O6 + C6H9I2NO + H2O = 2C6H10O5 + I2O5 + N2O2

   Reactants	Products
   C	12	12	✔️
   H	19	20	❌
   O	8	17	❌
   I	2	2	✔️
   N	1	2	❌

2. O is not balanced. Add 3 molecules of C6H9I2NO to the reactant (left-hand) side to balance Oxygen: C6H8O6 + 4C6H9I2NO + H2O = 2C6H10O5 + I2O5 + N2O2

   Reactants	Products
   C	30	12	❌
   H	46	20	❌
   O	11	17	❌
   I	8	2	❌
   N	4	2	❌

3. C is not balanced. Add 3 molecules of C6H10O5 to the product (right-hand) side to balance Carbon: C6H8O6 + 4C6H9I2NO + H2O = 5C6H10O5 + I2O5 + N2O2

   Reactants	Products
   C	30	30	✔️
   H	46	50	❌
   O	11	32	❌
   I	8	2	❌
   N	4	2	❌

4. H is not balanced. Add 2 molecules of H2O to the reactant (left-hand) side to balance Hydrogen: C6H8O6 + 4C6H9I2NO + 3H2O = 5C6H10O5 + I2O5 + N2O2

   Reactants	Products
   C	30	30	✔️
   H	50	50	✔️
   O	13	32	❌
   I	8	2	❌
   N	4	2	❌

5. O is not balanced. Add 18 molecules of H2O to the reactant (left-hand) side to balance Oxygen: C6H8O6 + 4C6H9I2NO + 21H2O = 5C6H10O5 + I2O5 + N2O2

   Reactants	Products
   C	30	30	✔️
   H	86	50	❌
   O	31	32	❌
   I	8	2	❌
   N	4	2	❌

6. I is not balanced. Add 3 molecules of I2O5 to the product (right-hand) side to balance Iodine: C6H8O6 + 4C6H9I2NO + 21H2O = 5C6H10O5 + 4I2O5 + N2O2

   Reactants	Products
   C	30	30	✔️
   H	86	50	❌
   O	31	47	❌
   I	8	8	✔️
   N	4	2	❌

7. N is not balanced. Add 1 molecule of N2O2 to the product (right-hand) side to balance Nitrogen: C6H8O6 + 4C6H9I2NO + 21H2O = 5C6H10O5 + 4I2O5 + 2N2O2

   Reactants	Products
   C	30	30	✔️
   H	86	50	❌
   O	31	49	❌
   I	8	8	✔️
   N	4	4	✔️

8. O is not balanced. Add 3 molecules of C6H8O6 to the reactant (left-hand) side to balance Oxygen: 4C6H8O6 + 4C6H9I2NO + 21H2O = 5C6H10O5 + 4I2O5 + 2N2O2

   Reactants	Products
   C	48	30	❌
   H	110	50	❌
   O	49	49	✔️
   I	8	8	✔️
   N	4	4	✔️

We could not determine all the steps needed to balance the equation using trial and error. This may mean it requires too many steps and the chemical equation is too complex to use this method, or that the equation is invalid (e.g. has 0 or non-integer coefficients). The algebraic method is likely better suited for balancing this equation.

If you would like to attempt to guess the next steps, the final element counts in the balanced equation should be:

19C6H8O6 + 4C6H9I2NO + 21H2O = 23C6H10O5 + 4I2O5 + 2N2O2

Reactants	Products
C	138	138	✔️
H	230	230	✔️
O	139	139	✔️
I	8	8	✔️
N	4	4	✔️

Practice Balancing

C6H8O6 - + + C6H9I2NO - + + H2O - + = C6H10O5 - + + I2O5 - + + N2O2 - +

Reactants	Products
C	12	6	❌
H	19	10	❌
O	8	12	❌
I	2	2	✔️
N	1	2	❌

Hint: The sum of the balanced coefficients is 73. See Step-By-Step Solution

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