Calculate PH Of 0.05M Potassium Hydrogen Phthalate, KHC8H4O4 ...

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SolveGuidesJoin / LoginUse appLogin0You visited us 0 times! Enjoying our articles? Unlock Full Access!Standard XIIChemistryQuestionCalculate pH of 0.05M potassium hydrogen phthalate, KHC8H4O4.H2C8H4O4+H2O→H3O++HC8H4O−4.pK1=2.94.HC8H4O−4+H2O→H3O++C8H4O−24.pK2=5.44.Open in AppSolutionVerified by Toppr

pH = (pK1+pK2) / 2 = (2.94 + 5.44)/2 = 4.19

Was this answer helpful?2Similar QuestionsQ1Calculate pH of 0.05M potassium hydrogen phthalate, KHC8H4O4.H2C8H4O4+H2O→H3O++HC8H4O−4.pK1=2.94.HC8H4O−4+H2O→H3O++C8H4O−24.pK2=5.44.View SolutionQ2H2O+H3PO4⇌H3O++H2PO4−;pK1=2.15H2O+H2PO−4⇌H3O++HPO2−4;pK2=7.20Hence, pH of 0.01MNaH2PO4 is:View SolutionQ3H3PO4+H2O⇌H3O++H2PO−4;pK1=2.15 H2PO−4+H2O⇌H3O++HPO−24;pK2=7.20 Hence,pHof0.01MNaH2PO4is:View SolutionQ4

H3PO4+H2O⇌H3O++H2PO−4 pK1=2.15

H2PO−4+H2O⇌H3O++HPO24− pK2=7.20

Hence pH of 0.01 M NaH2PO4 is:

View SolutionQ5H2O+H3PO−4⇋H3O++HPO2−4 Where, pK1=2.15 and pK2 = 7.2Then, pH of 0.01 M NaH2PO4 is:View Solution

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