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Offline osker246

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Calculate the following pH for the following
« on: April 23, 2009, 11:58:47 pm » Problem:Calculate the pH for each of the following:a) 0.10 M aniline (C6H5NH2) solution (Kb=4.3x10-10b)0.10 M C6H5NH3Cl solution (Kb=4.3x10-10Attempt:Well I'm having a hard time figuring out which both of those substances dissociate too. Part A I think I have worked out properly I think it goes something like this. C6H5NH2 + H2O <====> C6H5NH3+ + OH-I set up a ice chart showing that [OH-]=6.6x10-6, which pH=8.82Now for part B im having a hard time seeing what the dissociation reaction looks like. Is this is it?C6H5NH3Cl + H2O <====> C6H5NH3ClH+ +OH-I'm having a hard time figuring out what the conjuage base or acid to this would be. If anybody can help I would appreciate it. Thank you! Logged

Offline AWK

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Re: Calculate the following pH for the following
« Reply #1 on: April 24, 2009, 01:03:57 am » C6H5NH3+ + H2O <====> C6H5NH2 + H3O+ Logged AWK

Offline osker246

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Re: Calculate the following pH for the following
« Reply #2 on: April 24, 2009, 01:31:09 am » So C6H5NH2 is the conjugate acid correct? I would need solve for Ka and then set up an ICE chart to solve for [H3O+]? Logged

Offline AWK

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Re: Calculate the following pH for the following
« Reply #3 on: April 24, 2009, 02:35:45 am » aprox.[H3O+]= SQRT(Ka x [NH4+])note: Ka concerns anilinium cation Logged AWK

Offline Borek

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Re: Calculate the following pH for the following
« Reply #4 on: April 24, 2009, 03:11:06 am » Quote from: osker246 on April 24, 2009, 01:31:09 am
So C6H5NH2 is the conjugate acid correct?
No, it is a conjugate base. You have a reactionRH+ <-> R + H+RH+ is an acid, R is a conjugate base. Logged Chembuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info
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