Calculate The KHC8H4O4 Titer Of 0.125 M KOH. Give The Chemical ...

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Calculate the KHC8H4O4 titer of 0.125 M KOH. Give the chemical reactions involved Calculate the KHC8H4O4 titer of 0.125 M KOH. Give the chemical reactions involved

Added by Kevin G.

Step 1

10 g/mol H: 1.01 g/mol C: 12.01 g/mol O: 16.00 g/mol Adding these up, we get: 39.10 + 1.01*8 + 12.01 + 16.00*4 = 204.23 g/mol Show more…

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Transcript

- 00:01 Hello everyone today we are going to solve the following question so let's start solution step one at equivalence point the equivalence of acid is equal equivalent of of base step two k h c h4o4 asset k -o -h base that volume of the solution that volume of the solution is 1 l for both molar mass of khc8 h4o4204 gram per mole further 0 .1 .25 mole koha multiply 1 liter equal to x mole kh c8 h4 o4 multiply 1 liter equal to x mole kh c8 h4 o4 multiply 1 liter so x we get is 9 point oh sorry it's 0 .125 0 .125 mole of k h c8 h4 .4 hence the weight of kh c8 h4 0 .4 equal to 0 .125 multiply 204, which is 25 .5 gram. 03:56 Answer... Not the question you're looking for? Get a video solution from our educators in as few as 30 mins, plus an instant AI answer while you wait. Ask Now

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