Calculate The KHC8H4O4 Titer Of 0.125 M KOH. Give The Chemical ...

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Calculate the KHC8H4O4 titer of 0.125 M KOH. Give the chemical reactions involved Calculate the KHC8H4O4 titer of 0.125 M KOH. Give the chemical reactions involved

Added by Kevin G.

Chemistry: Structure and Properties Nivaldo Tro 2nd Edition

Step 1

10 g/mol H: 1.01 g/mol C: 12.01 g/mol O: 16.00 g/mol Adding these up, we get: 39.10 + 1.01*8 + 12.01 + 16.00*4 = 204.23 g/mol Show more…

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Transcript

00:01 Hello everyone today we are going to solve the following question so let's start solution step one at equivalence point the equivalence of acid is equal equivalent of of base step two k h c h4o4 asset k -o -h base that volume of the solution that volume of the solution is 1 l for both molar mass of khc8 h4o4204 gram per mole further 0 .1 .25 mole koha multiply 1 liter equal to x mole kh c8 h4 o4 multiply 1 liter equal to x mole kh c8 h4 o4 multiply 1 liter so x we get is 9 point oh sorry it's 0 .125 0 .125 mole of k h c8 h4 .4 hence the weight of kh c8 h4 0 .4 equal to 0 .125 multiply 204, which is 25 .5 gram. 03:56 Answer... Need help? Use Ace Ace is your personal tutor. It breaks down any question with clear steps so you can learn. Start Using Ace Ace is your personal tutor for learning Step-by-step explanations Instant summaries Summarize YouTube videos Understand textbook images or PDFs Study tools like quizzes and flashcards Listen to your notes as a podcast

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