Can Anyone Tell Me Where This Equation Came From? T = 2u / G ...

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Questions Courses Can anyone tell me where this equation came from? t = 2u / g. .... t =time, u = initial velocity, g. 1 answer below »

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Can anyone tell me where this equation came from? t = 2u / g. t = time, u = initial velocity, g = gravity acceleration Question: I throw a cricket ball as hard as I can upwards and find that it takes 3.8s to return to the ground. Estimate the throwing speed. Answer: Use constant acceleration equation model Neglecting my height: h = u t - (1/2)gt2 Factorizing: h = 0 when t = 0 (throw) and t = 2u / g t = 3.8s, g = 9.81ms-2 So u = tg / 2 = (3.8s * 9.81ms-2) / 2 = 18.6ms-1 ------------------------------------------------- My question: Where does t = 2u / g come from? Dec 02 2025 08:19 AM

Try Solving it with these steps:

These are AI-generated tips. For the verified answer, click “Solution.pdf.”

To understand the origin of the equation t = 2u / g, consider the following tips:

  • Review the basic equations of motion under constant acceleration.
  • Focus on the relationship between time, initial velocity, and acceleration due to gravity.
  • Analyze the scenario of an object thrown upwards and its motion characteristics.
  • Consider the symmetry of the motion: time up equals time down.
  • Derive the equation from the kinematic equations for vertical motion.
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1 Approved Answer

Expert Verified

Priyal g answered on December 04, 2025 4 Ratings (4 Votes)

Answer is in the... solution.pdf

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