(CH3)3P = O Exists But (CH3)3N = O Does Not. Give Reasons. - Toppr

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SolveGuidesJoin / LoginUse appLogin0You visited us 0 times! Enjoying our articles? Unlock Full Access!Standard XIIChemistryNitrogenQuestion(CH3)3P=O exists but (CH3)3N=O does not. Give reasons.Open in AppSolutionVerified by Toppr

Due to absence of d-orbitals in valence shell,cannot form dπ−pπ multiple bonds ,so nitrogen cannot form (CH3)3N=0.while in phosphorous, it has d-orbitals in its valance shell so, it can from dπ−pπ multiple bonds ,so (CH3)3P=0 exists

Was this answer helpful?1Similar QuestionsQ1(CH3)3P=O exists but (CH3)3N=O does not. Give reasons.View SolutionQ2Give reasons for the following:(i) (CH3)3P=O exists but (CH3)3N=O does not.(ii) Oxygen has less electron gain enthalpy with negative sign than sulphur.(iii) H3PO2 is a stronger reducing agent than H3PO3.View SolutionQ3Give reasons for the following:R3P=O exists but R3N=O does not, R is an alkyl group?View SolutionQ4Assertion :R3P = O exists but R3N = O does not exist. Reason: P is more electronegative than N.View SolutionQ5Give reasons for the following : (i) Where R is an alkyl group, R3P=O exists but R3N=O does not. (ii) PbCl4 is more covalent than PbCl2. (iii) At room temperature, N2 is not very reactive.View Solution

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