CH3CONH2 +Br2 /NAOH​

shiva04 shiva04
  • 11.03.2019
  • Biology
  • Secondary School
answered • expert verified CH3CONH2 +Br2 /NAOH​ See answer AfreenMohammedi AfreenMohammedi AfreenMohammedi

Hey mate...

When CH3CONH2 , acetamide reacts with KOH. Br2, we get methylamine,  CH3NH2

The reaction is

CH3CONH2   −→−Br2KOH   CH3NH2  + KBr

Here the reaction begins with the reaction with Br2, leading to formation of isocyanate which further hydrolysis to give the desired product.

Hope this helps u....

Please make it BRAINLIEST answer :)

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