CH3COOH NH3 (A) Heat (B) P2O5 (C) Na + C2H5OH (D) A. Ester B ...

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The product (D) in the following sequence of reactions is: CH3COOH NH3 (A) Heat (B) P2O5 (C) Na + C2H5OH (D) A. ester B. amine C. acid D. alcohol The product (D) in the following sequence of reactions is: CH3COOH NH3 (A) Heat (B) P2O5 (C) Na + C2H5OH (D) A. ester B. amine C. acid D. alcohol

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Chemistry: Structure and Properties Nivaldo Tro 2nd Edition

Step 1

This reaction forms an ammonium salt, CH3COONH4 (ammonium acetate). \[ \text{CH}_3\text{COOH} + \text{NH}_3 \rightarrow \text{CH}_3\text{COONH}_4 \] Show more…

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In the following sequence of reactions: $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH} \stackrel{\mathrm{KMnO}_{4}}{\longrightarrow}(\mathrm{a}) \stackrel{\mathrm{SOCl}_{2}, \mathrm{NH}_{3}}{\longrightarrow}$ (b) $\mathrm{Br}_{2}+\mathrm{NaOH}$ (c) the end product (c) is (a) Acetone (b) Ethylamine (c) Acetic acid (d) Methyl amine

In the following sequence of reactions: $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH} \quad \mathrm{KMnO}_{4}$ (a) $\mathrm{SOCl}_{2}, \mathrm{NH}_{3}{\longrightarrow}$ $\mathrm{Br}_{2}+\mathrm{NaOH}$ (b) (C) the end product (C) is (a) Acetone (b) Ethylamine (c) Acetic acid (d) Methyl amine

In the following sequence of reactions: $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH} \quad \mathrm{KMnO}_{4}$ (a) $\mathrm{SOCl}_{2}, \mathrm{NH}_{3}{\longrightarrow}$ $\mathrm{Br}_{2}+\mathrm{NaOH}$ (b) (C) the end product (C) is (a) Acetone (b) Ethylamine (c) Acetic acid (d) Methyl amine

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Transcript

00:01 Hi, here we have to find the final product d. 00:05 So, first of all, if we draw the structure of a cs3, c -o -h, it is an a etanoic acid and when it react with ammonia, we know that ammonia is a base. 00:25 So here, acid -based reaction will take place and salt is formed like this. 00:30 C s3 c -o -h and this oxygenally converted into negative and n -s -3 will form as. 00:44 So this is a salt, this is a a product, this is salt is formed by the acid -based reaction. 00:52 Now if we heat this product, the water molecule is always released and this negative charge will takes place here so we will get athenamide so this is the product ethanolide now when this ethanolide react with p2 .05 now p2 .5 is a dehydrating agent dehydrating means it will remove one matter water molecule from this compound and when this water molecule remove from here means one oxygen and two hydrogen from here we will get a triple bond between this carbon and nitrogen this is a c product now the c product react with sodium plus c2 h5 -4h here sodium is metal and in the presence of metal there is always takes place a reduction means hydrogen will provide this reagent to this carbon and nitrogen nitrogen and we will get this final product... Need help? Use Ace Ace is your personal tutor. It breaks down any question with clear steps so you can learn. Start Using Ace Ace is your personal tutor for learning Step-by-step explanations Instant summaries Summarize YouTube videos Understand textbook images or PDFs Study tools like quizzes and flashcards Listen to your notes as a podcast

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