Convert 6.67×10^11 Nm^2 Kg^-2 In CGS System

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bhatmunaza1p81qv4 bhatmunaza1p81qv4
  • 01.05.2018
  • Physics
  • Secondary School
answered • expert verified Convert 6.67×10^11 Nm^2 kg^-2 in CGS system See answers SerenaBochenek SerenaBochenek

The answer to the question is \ 6.67\times 10^{14}\ dyne\ cm^2\ gram^{-2}

CALCULATION:

We know that 1 N = 10^{5}\ dyne

one metre = 100 cm

                 = 10^{2}\ cm

Again one 1 kg = 1000 gram

                         = 10^{3}\ gram.

We are asked to convert 6.67\times\10^{11}\ Nm^2\ kg^{-2} into CGS system.

We have  6.67\times\ 10^{11}\ Nm^2\ kg^{-2}

                 =\ 6.67\times 10^{11} (10^{5})dyne\times (100cm)^{2}\times (1000\ gram)^{-2}

                 =\ 6.67\times 10^{11} \times 10^5\times 10^4\times 10^{-6}\ dyne\ cm^2\ gram^{-2}

                 =\ 6.67\times 10^{14}\ dyne\ cm^2\ gram^{-2}   [ans]

AJAYMAHICH AJAYMAHICH AJAYMAHICH We know that in SIG = 6.67 x 10-11 Nm2/kg2so, when expressed in VGS units we shall convert N to dynes, m to cm and kg to g, thusG = 6.67 x 10-11 x [(105dynes x (102)2cm2 ) / (103)2 g2]=  6.67 x 10-11 x [ (105 x 104 ) / 106 ] thus,in CGS systemG = 6.67 x 10-8 dyne.cm2/g2

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