Cu(OH)2 + HCl = Cu(OH)Cl + H2O - Chemical Equation Balancer

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Balanced Chemical Equation

Cu(OH)2 + HCl → Cu(OH)Cl + H2O Reaction Info Balance Another Equation Step-by-Step Solution Practice Balancing

Reaction Information Disclaimer

Word Equation

Cupric Hydroxide + Hydrogen Chloride = Belloite + Water

Cu(OH)2 + HCl = Cu(OH)Cl + H2O is a Double Displacement (Acid-Base) reaction where one mole of Cupric Hydroxide [Cu(OH)2] and one mole of Hydrogen Chloride [HCl] react to form one mole of Belloite [Cu(OH)Cl] and one mole of Water [H2O]

Reaction Type

Double Displacement (Acid-Base)

List of AcidsHClList of BasesCu(OH)2

Reactants

• Cupric Hydroxide - Cu(OH)2

  Cu(Oh)2 Cu(OH)2 Molar Mass Cu(OH)2 Oxidation Number

• Hydrogen Chloride - HCl

  Hcl HCl Molar Mass HCl Bond Polarity HCl Oxidation Number

Products

• Belloite - Cu(OH)Cl

  Ima1998-054 Cu(OH)Cl Molar Mass Cu(OH)Cl Oxidation Number

• Water - H2O

  Hydroxic Acid H₂O [Oh2] Aqua Pure Water Hydrogen Oxide Oxidane Dihydrogen Oxide H2O Molar Mass H2O Oxidation Number

Show Chemical Structure Image

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [Cu(OH)Cl] [H2O] ) / ( [Cu(OH)2] [HCl] )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -(Δ[Cu(OH)2] / Δt) = -(Δ[HCl] / Δt) = (Δ[Cu(OH)Cl] / Δt) = (Δ[H2O] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
• Ionic charges are not yet supported and will be ignored.
• Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
• Compound states [like (s) (aq) or (g)] are not required.
• You can use parenthesis () or brackets [].

How To Balance Equations

Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured.

Read our article on how to balance chemical equations or ask for help in our chat.

Examples

• Cupric Hydroxide + Hydrogen Chloride = Belloite + Water
• Cu(OH)2 + HCl + KI = CuI + I2 + KCl + H2O
• Cu(OH)2 + HCl = Cl2Cu + H2O
• Cu(OH)2 + HCl = Cu + Cl + H2O
• Cu(OH)2 + HCl = Cu(Cl)2 + H2O
• Cu(OH)2 + HCl = Cu2(OH)3Cl + H2O
• Cu(OH)2 + HCl = Cu2Cl(OH)3 + H2O
• Cu(OH)2 + HCl = CuCl + H(OH)2
• Cu(OH)2 + HCl = CuCl + H20 + OH
• C2H2 + Ag2O + NH3 = Ag2C2 + H2O + NH3
• PBCO3 + HNO3 = PB(NO3)2 + CO2 + H2O
• C6H4(COOC2H5)2 + H2O = C6H4(COOH)2 + C2H5OH
• KAl(SO4)2 + K2S + H2O = Al(OH)3 + H2S + K2O4S
• Recently Balanced Equations

Balance Cu(OH)2 + HCl = Cu(OH)Cl + H2O Using the Algebraic Method

To balance the equation Cu(OH)2 + HCl = Cu(OH)Cl + H2O using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a Cu(OH)2 + b HCl = c Cu(OH)Cl + d H2O

Step 2: Create a System of Equations

Create an equation for each element (Cu, O, H, Cl) where each term represents the number of atoms of the element in each reactant or product.

Cu: 1a + 0b = 1c + 0d O: 2a + 0b = 1c + 1d H: 2a + 1b = 1c + 2d Cl: 0a + 1b = 1c + 0d

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination

• 1a - 1c = 0
• 2a - 1c - 1d = 0
• 2a + 1b - 1c - 2d = 0
• 1b - 1c = 0

Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 1 0 -1 0 0] [ 2 0 -1 -1 0] [ 2 1 -1 -2 0] [ 0 1 -1 0 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

• a = 1 (Cu(OH)2)
• b = 1 (HCl)
• c = 1 (Cu(OH)Cl)
• d = 1 (H2O)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

Cu(OH)2 + HCl = Cu(OH)Cl + H2O

Reactants	Products
Cu	1	1	✔️
O	2	2	✔️
H	3	3	✔️
Cl	1	1	✔️

Since there is an equal number of each element in the reactants and products of Cu(OH)2 + HCl = Cu(OH)Cl + H2O, the equation is balanced.

Balance Cu(OH)2 + HCl = Cu(OH)Cl + H2O Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in Cu(OH)2 + HCl = Cu(OH)Cl + H2O must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)			Products (Right Hand Side)
Reactants	Products
Cu(OH)2	HCl	Total	Cu(OH)Cl	H2O	Total
Cu	1	1	1	1	✔️
O	2	2	1	1	2	✔️
H	2	1	3	1	2	3	✔️
Cl	1	1	1	1	✔️

The number of atoms of each element on both sides of Cu(OH)2 + HCl = Cu(OH)Cl + H2O is equal which means that the equation is already balanced and no additional work is needed.

Practice Balancing

Cu(OH)2 - + + HCl - + = Cu(OH)Cl - + + H2O - +

Reactants	Products
Cu	1	1	✔️
O	2	2	✔️
H	3	3	✔️
Cl	1	1	✔️

Hint: The sum of the balanced coefficients is 4. See Step-By-Step Solution

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