Cu(OH)2 + NH3*H2O = Cu(NH3)4(OH)2 + H2O - Chemical Equation ...
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Balanced Chemical Equation
Cu(OH)2 + 4NH3·H2O → Cu(NH3)4(OH)2 + 4H2OWarning: One of the compounds in Cu(OH)2 + NH3*H2O = Cu(NH3)4(OH)2 + H2O is unrecognized. Verify 'NH3*H2O' is entered correctly.
Reaction Info Balance Another Equation Step-by-Step Solution Practice BalancingReaction Information
Cu(OH)2+NH3·H2O=Cu(NH3)4(OH)2+H2OReaction Type
Double Displacement (Metathesis)
Reactants
Cupric Hydroxide - Cu(OH)2
Cu(Oh)2 Cu(OH)2 Molar Mass Cu(OH)2 Oxidation Number- NH3·H2O
Products
Tetraamminecopper Dihydroxide - Cu(NH3)4(OH)2
Cu(NH3)4(OH)2 Molar Mass Cu(NH3)4(OH)2 Oxidation NumberWater - H2O
Hydroxic Acid H₂O [Oh2] Aqua Pure Water Hydrogen Oxide Oxidane Dihydrogen Oxide H2O Molar Mass H2O Oxidation Number
Instructions
To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.
- Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
- Ionic charges are not yet supported and will be ignored.
- Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
- Compound states [like (s) (aq) or (g)] are not required.
- You can use parenthesis () or brackets [].
How To Balance Equations
Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured.
Read our article on how to balance chemical equations or ask for help in our chat.
Examples
- Cu(OH)2 + NH3*H2O = (Cu(NH3)2)(OH)2 + H2O
- Cu(OH)2 + NH3*H2O = (Cu(NH3)4)(OH)2 + H2O
- Cu(OH)2 + NH3*H2O = (Cu(NH3)4){2+} + H2O + OH{-}
- Cu(OH)2 + NH3*H2O = (Cu(NH3)6)(OH)2 + H2O
- Cu(OH)2 + NH3*H2O = (NH4)2(Cu(OH)4)
- Cu(OH)2 + NH3*H2O = Cu(NH3) + OH + H2O
- Cu(OH)2 + NH3*H2O = Cu(NH3)4 + OH + H2
- Cu(OH)2 + NH3*H2O = Cu(NH3)4 + OH + H2O
- C2H6O = C4H6 + H2O + H
- CH3CH2CH(CH)COOH + Nh3 = CH3CH2CH(Nh2)COOH + Nh4CH
- FeBr3 + HCl = FeCl2 + BrH + Br2
- C6H12O6 + KMnO4 + H2SO4 = CO2 + MnO4S + K2O4S + H2
- Recently Balanced Equations
Balance Cu(OH)2 + NH3*H2O = Cu(NH3)4(OH)2 + H2O Using the Algebraic Method
To balance the equation Cu(OH)2 + NH3*H2O = Cu(NH3)4(OH)2 + H2O using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.
Step 1: Label Each Compound With a Variable
Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.
a Cu(OH)2 + b NH3·H2O = c Cu(NH3)4(OH)2 + d H2O
Step 2: Create a System of Equations
Create an equation for each element (Cu, O, H, N) where each term represents the number of atoms of the element in each reactant or product.
Cu: 1a + 0b = 1c + 0d O: 2a + 1b = 2c + 1d H: 2a + 5b = 14c + 2d N: 0a + 1b = 4c + 0dStep 3: Solve For All Variables
Use substitution, Gaussian elimination, or a calculator to solve for each variable.
Using Substitution or Elimination- 1a - 1c = 0
- 2a + 1b - 2c - 1d = 0
- 2a + 5b - 14c - 2d = 0
- 1b - 4c = 0
Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:
[ 1 0 -1 0 0] [ 2 1 -2 -1 0] [ 2 5 -14 -2 0] [ 0 1 -4 0 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-StepSimplify the result to get the lowest, whole integer values.
- a = 1 (Cu(OH)2)
- b = 4 (NH3*H2O)
- c = 1 (Cu(NH3)4(OH)2)
- d = 4 (H2O)
Step 4: Substitute Coefficients and Verify Result
Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.
Cu(OH)2 + 4 NH3·H2O = Cu(NH3)4(OH)2 + 4 H2OReactants | Products | ||
---|---|---|---|
Cu | 1 | 1 | ✔️ |
O | 6 | 6 | ✔️ |
H | 22 | 22 | ✔️ |
N | 4 | 4 | ✔️ |
Balance Cu(OH)2 + NH3*H2O = Cu(NH3)4(OH)2 + H2O Using Inspection
The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in Cu(OH)2 + NH3*H2O = Cu(NH3)4(OH)2 + H2O must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.
Step 1: Count the number of each element on the left and right hand sides
Reactants (Left Hand Side) | Products (Right Hand Side) | ||||||
---|---|---|---|---|---|---|---|
Reactants | Products | ||||||
Cu(OH)2 | NH3·H2O | Total | Cu(NH3)4(OH)2 | H2O | Total | ||
Cu | 1 | 1 | 1 | 1 | ✔️ | ||
O | 2 | 1 | 3 | 2 | 1 | 3 | ✔️ |
H | 2 | 5 | 7 | 14 | 2 | 16 | ❌ |
N | 1 | 1 | 4 | 4 | ❌ |
Step 2: Multiply coefficients for compounds to balance out each element
For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your best judgement and be prepared to go back and try the other options.
- N is not balanced. Add 3 molecules of NH3·H2O to the reactant (left-hand) side to balance Nitrogen: Cu(OH)2 + 4NH3·H2O = Cu(NH3)4(OH)2 + H2O
Reactants Products Cu 1 1 ✔️ O 6 3 ❌ H 22 16 ❌ N 4 4 ✔️ - O is not balanced. Add 3 molecules of H2O to the product (right-hand) side to balance Oxygen: Cu(OH)2 + 4NH3·H2O = Cu(NH3)4(OH)2 + 4H2O
Reactants Products Cu 1 1 ✔️ O 6 6 ✔️ H 22 22 ✔️ N 4 4 ✔️
Step 3: Verify that the equation is balanced
Since there are an equal number of atoms of each element on both sides, the equation is balanced.
Cu(OH)2 + 4NH3·H2O = Cu(NH3)4(OH)2 + 4H2OPractice Balancing
Cu(OH)2 - + + NH3·H2O - + = Cu(NH3)4(OH)2 - + + H2O - +Reactants | Products | ||
---|---|---|---|
Cu | 1 | 1 | ✔️ |
O | 3 | 3 | ✔️ |
H | 7 | 16 | ❌ |
N | 1 | 4 | ❌ |
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