Evaluate: Limit X→0 E^x - E^-x-2log(1 + X)xsinx . - Toppr
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SolveGuidesJoin / LoginUse appLogin0You visited us 0 times! Enjoying our articles? Unlock Full Access!Standard XIIMathematicsQuestionEvaluate:limx→0ex−e−x−2log(1+x)xsinx.Open in AppSolutionVerified by Toppr
Now,limx→0ex−e−x−2log(1+x)xsinx (00) form.Now applying L'Hospital's rule we get,=limx→0ex+e−x−2(1+x)xcosx+sinx(00) form.Now applying L'Hospital's rule we get,=limx→0ex−e−x+2(1+x)2−xsinx+2cosx=22=1.
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